4. i. Using the data at the bottom of the question, calculate the enthalpy of formation of W(CO)6(S). ii. At 298 K, the enthalpies of sublimation of W(CO)6(s) and of W(s) are 75.6 and 849.4 kJ mol¹ respectively. Calculate the mean (W-CO) bond dissociation enthalpy in W(CO)6. The following enthalpies of combustion have been measured at 298 K. W(s) + 1.5 O2(g) → WO3(s) W(CO)6(s) + 4.5 O2(g) → WO3(s) + 6CO2(g) - CO(g) + 0.5 O2(g) → CO2(g) -> C(s) + O2(g) → CO2(g) ACH₁ =-842.9 kJ mol¯¹ AcH2-2242.7 kJ mol¯¹ AcH3 = -282.8 kJ mol¹ AcH4-393.5 kJ mol¹

4. i. Using the data at the bottom of the question, calculate the enthalpy of formation of W(CO)6(S). ii. At 298 K, the enthalpies of sublimation of W(CO)6(s) and of W(s) are 75.6 and 849.4 kJ mol¹ respectively. Calculate the mean (W-CO) bond dissociation enthalpy in W(CO)6. The following enthalpies of combustion have been measured at 298 K. W(s) + 1.5 O2(g) → WO3(s) W(CO)6(s) + 4.5 O2(g) → WO3(s) + 6CO2(g) - CO(g) + 0.5 O2(g) → CO2(g) -> C(s) + O2(g) → CO2(g) ACH₁ =-842.9 kJ mol¯¹ AcH2-2242.7 kJ mol¯¹ AcH3 = -282.8 kJ mol¹ AcH4-393.5 kJ mol¹

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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