4. Here are the pKa values for Question 2. Did you get the answer correct in which direction the equilibrium lies for each reaction? Explain why or why not. (Hint: You may want to first identify your acid and base followed by comparing the pKa values of your acid and conjugate acid). pka H20 = 15.7, NH4* = 9.8, NH3 = 33 a. NH3 + H20 5 NH4 + -OH b. NH2- + H20 5 NH3 + -OH
4. Here are the pKa values for Question 2. Did you get the answer correct in which direction the equilibrium lies for each reaction? Explain why or why not. (Hint: You may want to first identify your acid and base followed by comparing the pKa values of your acid and conjugate acid). pka H20 = 15.7, NH4* = 9.8, NH3 = 33 a. NH3 + H20 5 NH4 + -OH b. NH2- + H20 5 NH3 + -OH
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![4. Here are the pKa values for Question 2. Did you get the answer correct in
which direction the equilibrium lies for each reaction? Explain why or why
not.
(Hint: You may want to first identify your acid and base followed by comparing the
pKa values of your acid and conjugate acid).
pKa H20 = 15.7, NH4* = 9.8, NH3 = 33
a.
NH3 + H20 5 NH4* + -OH
b.
NH2- + H20 5 NH3 + -OH](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdc024bdf-b8f8-4bd4-bb69-1e67cee7f79e%2F768033ff-bf47-4b8c-8b47-43aaf2b117a0%2Foeup2k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4. Here are the pKa values for Question 2. Did you get the answer correct in
which direction the equilibrium lies for each reaction? Explain why or why
not.
(Hint: You may want to first identify your acid and base followed by comparing the
pKa values of your acid and conjugate acid).
pKa H20 = 15.7, NH4* = 9.8, NH3 = 33
a.
NH3 + H20 5 NH4* + -OH
b.
NH2- + H20 5 NH3 + -OH
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