4. Given the schematic notation: Cu | Cu²+ (0.0200 M) || Ag* (0.020o M) | Ag, calculate the cell potential of this system. Show all calculation. Cu(s) → Cu²*(aq) + 2e- E° = 0.34 V Ag*(aq) + e- → Ag(s) E° = 0.80 V %3D E cell = E° cell 0.0592 V -log Q 0.0592 E = E° 1 -log 0.0200 0.0592 1 log 0.0200 EAg+ Jag = 0.80 = 0.699 V п 0.0592 1 E Cu2+ /Cu = 0.34 - log 0.239 V n 0.0200 E® cell = Eg+ – Ecu²+ E° cell = 0.699 V - 0.239 V E° cell = 0.46 V was com

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GOOD DAY MAAM/SIR. THIS IS ALL ABOUT ELECTROCHEMISTRY LABORATORY 7, HOWEVER WE ARE IN A VIRTUAL CLASS ONLY SO WE WERE NOT ABLE TO DO THE LABORATORY HUHUH PLEASE HELP ME ..... THERE IS ALREADY INPUTTED OBSERVATIONS FROM THE VIDEO BUT PLEASE CORRECT ME IF IM WRONG.. PLEASE..

I WILL GIVE HELPFUL RATING AFTER.. I PROMISE NOT TO GIVE UNHELPFUL RATING..


This is the laboratory video: https://www.youtube.com/watch?v=-ixqpuEUgmU&list=PLF4C_4-DJPh4eLU8EFYnI7Sz9hppvapJn&index=5

4. Given the schematic notation: Cu | Cu²+ (0.0200 M) || Ag* (0.020o M) | Ag, calculate
the cell potential of this system. Show all calculation.
Cu(s) → Cu²+(aq) + 2e¯
E° = 0.34 V
Ag*(aq) + e- → Ag(s)
E° = 0.80 V
%3D
E cell = E° cell
0.0592 V
-log Q
0.0592
1
-log
0.0200
E = E®
0.0592
1
-log
0.0200
EAg+ Jag = 0.80
= 0.699 V
п
E Cu2+ /Cu = 0.34 -
0.0592
1
log
0.239 V
n
0.0200
E® cell = Eg+ – Ecu²+
E° cell = 0.699 V – 0.239 V
E° cell = 0.46 V
was
com
Transcribed Image Text:4. Given the schematic notation: Cu | Cu²+ (0.0200 M) || Ag* (0.020o M) | Ag, calculate the cell potential of this system. Show all calculation. Cu(s) → Cu²+(aq) + 2e¯ E° = 0.34 V Ag*(aq) + e- → Ag(s) E° = 0.80 V %3D E cell = E° cell 0.0592 V -log Q 0.0592 1 -log 0.0200 E = E® 0.0592 1 -log 0.0200 EAg+ Jag = 0.80 = 0.699 V п E Cu2+ /Cu = 0.34 - 0.0592 1 log 0.239 V n 0.0200 E® cell = Eg+ – Ecu²+ E° cell = 0.699 V – 0.239 V E° cell = 0.46 V was com
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