4. Given the equation y = (sinx)cosx %3D Determine dy/dx. O (sinx)cosx-1 cos?x - (sinx)cosx- In(sinx) (sinx)cosx cosx sinx - (sinx)cosx In(sinx). (sinx)cosx cosx cotx + (sinx)cosx sinx In(sinx) (sinx)cosx+1 cos²x + (sinx)cosx- In(sinx) None of the choices.

Q: -y = sin Va

A:

Q: cos (2x) dx sinx+cosx COS Evaluate:

A: the given integral is: ∫cos(2x)sinx+cosxdx we have to evaluate the given integral.

Q: y=(sinx)cosx

A:

Q: y = sin(x + y)

A:

Q: sin(2w)dw =

A:

Q: COS Cos 3x dx CoS

A: I am going to solve the given problem by using some simple calculus to get the required result of…

Q: Differentiate y=sinx+cosx+tanx

A:

Q: COs 2x cotx x – tanx %3D sinx · cOsx

A:

Q: eft co Evaluate cos² (9x) dx.

A:

Q: cos x sin x = csc 2x cos 3x sec 2x

A:

Q: • / esc" (2) dz (z) dz 19.

A:

Q: y = sin 2rx

A:

Q: y = Secx ( sinx+ Cosx)

A: Given, y=secxsinx+cosx And we have to find the dydx.

Q: Describe some similarities and differences between y = cosx and y = secx.

A: Explanation of the answer is as follows