Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:**Question 4: Crossed Aldol Reaction Product**
**Problem Statement:**
Give the crossed aldol product for the following reaction.
**Reaction Scheme:**
Reactants:
- 3-Methylbutanal (C5H10O)
- Benzaldehyde (C7H6O)
Conditions:
- NaOH (aq)
- 25°C
**Diagram Explanation:**
- The provided image presents two reactants involved in an aldol reaction.
- The first reactant is 3-methylbutanal, a molecule with the structure comprising a formyl group (–CHO) attached to a butyl chain that is substituted with a methyl group.
- The second reactant is benzaldehyde, characterized by a benzene ring attached to an aldehyde group (–CHO).
- These reactants are combined under basic aqueous conditions (NaOH) at room temperature (25°C).
The outcome of this reaction is an aldol product, formed by the nucleophilic addition of the enolate ion of 3-methylbutanal to the carbonyl group of benzaldehyde. The exact structure of the product isn't shown in the image, but will typically be a β-hydroxy ketone or aldehyde based on these reactants.
Understanding the principles of aldol condensation, particularly the crossed aldol reaction (where two different aldehydes/ketones participate), is essential for deducing the final β-hydroxy product.
**Key Learning Points:**
- Crossed aldol reactions involve two different aldehydes/ketones.
- The reaction generally requires a base (here NaOH) to generate the enolate ion.
- The reaction temperature is often kept around room temperature to control the reaction kinetics.
- The product is typically a β-hydroxy aldehyde or ketone, subject to further dehydration to form an α,β-unsaturated carbonyl compound.
For further understanding, explore detailed mechanisms of aldol reactions and practice with varied reactants to gain proficiency in predicting aldol products.
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