4. Give the crossed aldol product for the following reaction. NaOH (aq) + H. 25 °C

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**Question 4: Crossed Aldol Reaction Product**

**Problem Statement:**  
Give the crossed aldol product for the following reaction.

**Reaction Scheme:**  
Reactants:
   - 3-Methylbutanal (C5H10O)
   - Benzaldehyde (C7H6O)
   
Conditions:  
   - NaOH (aq)
   - 25°C

**Diagram Explanation:**
- The provided image presents two reactants involved in an aldol reaction.
- The first reactant is 3-methylbutanal, a molecule with the structure comprising a formyl group (–CHO) attached to a butyl chain that is substituted with a methyl group.
- The second reactant is benzaldehyde, characterized by a benzene ring attached to an aldehyde group (–CHO).
- These reactants are combined under basic aqueous conditions (NaOH) at room temperature (25°C). 

The outcome of this reaction is an aldol product, formed by the nucleophilic addition of the enolate ion of 3-methylbutanal to the carbonyl group of benzaldehyde. The exact structure of the product isn't shown in the image, but will typically be a β-hydroxy ketone or aldehyde based on these reactants.

Understanding the principles of aldol condensation, particularly the crossed aldol reaction (where two different aldehydes/ketones participate), is essential for deducing the final β-hydroxy product. 

**Key Learning Points:**
- Crossed aldol reactions involve two different aldehydes/ketones.
- The reaction generally requires a base (here NaOH) to generate the enolate ion.
- The reaction temperature is often kept around room temperature to control the reaction kinetics.
- The product is typically a β-hydroxy aldehyde or ketone, subject to further dehydration to form an α,β-unsaturated carbonyl compound.

For further understanding, explore detailed mechanisms of aldol reactions and practice with varied reactants to gain proficiency in predicting aldol products.
Transcribed Image Text:**Question 4: Crossed Aldol Reaction Product** **Problem Statement:** Give the crossed aldol product for the following reaction. **Reaction Scheme:** Reactants: - 3-Methylbutanal (C5H10O) - Benzaldehyde (C7H6O) Conditions: - NaOH (aq) - 25°C **Diagram Explanation:** - The provided image presents two reactants involved in an aldol reaction. - The first reactant is 3-methylbutanal, a molecule with the structure comprising a formyl group (–CHO) attached to a butyl chain that is substituted with a methyl group. - The second reactant is benzaldehyde, characterized by a benzene ring attached to an aldehyde group (–CHO). - These reactants are combined under basic aqueous conditions (NaOH) at room temperature (25°C). The outcome of this reaction is an aldol product, formed by the nucleophilic addition of the enolate ion of 3-methylbutanal to the carbonyl group of benzaldehyde. The exact structure of the product isn't shown in the image, but will typically be a β-hydroxy ketone or aldehyde based on these reactants. Understanding the principles of aldol condensation, particularly the crossed aldol reaction (where two different aldehydes/ketones participate), is essential for deducing the final β-hydroxy product. **Key Learning Points:** - Crossed aldol reactions involve two different aldehydes/ketones. - The reaction generally requires a base (here NaOH) to generate the enolate ion. - The reaction temperature is often kept around room temperature to control the reaction kinetics. - The product is typically a β-hydroxy aldehyde or ketone, subject to further dehydration to form an α,β-unsaturated carbonyl compound. For further understanding, explore detailed mechanisms of aldol reactions and practice with varied reactants to gain proficiency in predicting aldol products.
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