**4) For each of the following pairs, give the relationship between the two compounds. You may ignore conformational isomerism here, and any conformers may be considered to be identical compounds.**a. - Left compound: 1,1-difluoro-2-methylpropane- Right compound: 2,2-difluoro-1-methylpropaneb. - Left compound: Cyclohexanol derivative with substituents on the 4 and 5 positions.- Right compound: Cyclohexanol derivative with substituents on the 1 and 2 positions.c. - Left compound: 2-methylthiobutanol- Right compound: 3-methylthiobutanold. - Both compounds are methyl-substituted cyclohexane derivatives with the same substituent positions.e. - Both compounds are dibromobenzene derivatives.f. - Both compounds are bromohydroxybenzene derivatives.Each pair of structures represents variations in isomerism, such as constitutional isomers or stereoisomers. Analyze the relationships between functional groups and substituent positions to determine the specific type of isomerism.

Hello. Since your question has multiple sub-parts, the first three sub-parts shall only be solved in this case. If all the sub-parts are needed, resubmit the question and specify it.Since the configurations of the two compounds are S and R respectively, thus these are enantiomers.Since the position of the OH group is changed, thus these are position isomers. Since the configuration of the two compounds is S and R respectively, thus these are enantiomers.