Answered: 4. For each case, draw at least one…

4. For each case, draw at least one possible constitutional isomer that is consistent with the molecular formula and the IR spectrum.

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL4: Proton (1h) Nmr Spectroscopy

Section: Chapter Questions

Problem 2E

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Concept explainers

Analyzing and Predicting Spectroscopic Data

The interaction of electromagnetic radiation with the structure of molecules in the sample and their study is referred spectroscopy. Several spectroscopic methods are used to acquire sample information, and these methods are proved to be accurate, fast, and non-destructive. The information obtained about the content and composition of molecules from these spectroscopic methods is called spectroscopic data.

Question

4. For each case, draw at least one possible constitutional isomer that is consistent with
the molecular formula and the IR spectrum.

b. MW 88, CsH120
80
68
40
20
4000
35ee
3000
2506
20ee
150e
19ee
1488
STET
949
rce

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4. For each case, draw at least one possible constitutional isomer that is consistent with the molecular formula and the IR spectrum.
5. For each of the following spectra, draw one possible constitutional isomer that is consistent with the molecular formula, any given background information, and the IR spectrum.
Based on the picture below what is the: Number of signals, and the parts of sheding and spliting?
How many signals would be in a CNMR AND HNMR for this product? Please explain in depth.
Please give me the right answer
A.) How many signals does the HNMR of the unknown C6H14O have? B.)Whats the ratio between the number of different hydrogens in the unknown compound C6H14O? C.)Explain splitting patterns of all the signals (in depth if possible the lecture confused me). D.)Explain the chemical shifts of the signals based upon the locations of hydrogens relative to the desheilding groups if any are present in the compound. For A. I think there are 4 signals. For B. I think the ratio is 1:1:3:9 for the hydrogens on the HNMR spectrum. For the last 2 questions (C. and D.) the lecture confused me so an in depth of how you found the answer would be greatly appreciated. Also the unknown for the attached HNMR is C6H14O.
also specify the integration valuesfor all Hs in each molecule.
also specify the integration valuesfor all Hs in each molecule.
a) b) 6) Consider the two carbonyl compounds below. The signal that corresponds to the hydrogens directly next to the carbonyl (called the a hydrogens) have been boxed on both spectra. In structure a, the boxed a hydrogen signal occurs at 2.4 ppm. In structure b, the boxed a hydrogen signal occurs at 3.61 ppm. Please explain the observed downfield shift between the two compounds. 1.60 M 0.93 2.40 2.10 u 3.61 O 2.25 2.25 PPM 2 PPM
please help?
help me with the part on spin-spin splitting diagram please
fa) In the 400 MHz spectrum of a certain , separated by 4 ppm. The observed compound, there separated by 4 ppm. The observed coupling constant is 7 Hz. 6) What is this separation expressed in are two doublets Hz? f) In a 600-MHz instrument, what is the separation in Hz and in ppm?