4. For a ring of radius a and uniform line density A the electric field f at position (0,0,z) is given by E, = %3D [see figure 4]. If a=10cm, A = 015n C then 240(a2+22) (a) at z = 0, z = z = 2- and z = 00 the electric field is given as E = 0, E. =1.67399 x 10 N/C,E, = 2.17458 x 10 N/C, E = 1.53766 x 10° N/C and E, = 0 respectively (True,False) (b) At z = - the electric field is maximum (True,False) (c) The maximum force on a point charge q = 1µC is F = qEmax) = 2.17458N (True,False)
4. For a ring of radius a and uniform line density A the electric field f at position (0,0,z) is given by E, = %3D [see figure 4]. If a=10cm, A = 015n C then 240(a2+22) (a) at z = 0, z = z = 2- and z = 00 the electric field is given as E = 0, E. =1.67399 x 10 N/C,E, = 2.17458 x 10 N/C, E = 1.53766 x 10° N/C and E, = 0 respectively (True,False) (b) At z = - the electric field is maximum (True,False) (c) The maximum force on a point charge q = 1µC is F = qEmax) = 2.17458N (True,False)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
#4
![E,
dE
Q-AL
- L/2
+L/2
dx
(x0,0)
Figure 3:
E,
9(0.0.z)
Q-2xa A
Figure 4:
4. For a ring of radius a and uniform line density A the electric field f at position (0,0,z) is given by E, =
4re0(a2+z2)
daz
3.
2e0(a2+z2) 2
[see figure 4]. If a=10cm, A =
.015n C
then
(a) at z = 0, z = , z = , z =
2 and z = o the electric field is given as E, = 0, E = 1.67399 x 10° N/C,E,
= 2.17458 x 10 N/C,
%3D
2/2
Ez = 1.53766 × 106 N/C and E, = 0 respectively (True,False)
(b) At z = the electric field is maximum (True,False)
%3D
(c) The maximum force on a point charge q 1µC is F =
qEa) = 2.17458N (True,False)
%3D
E,
dE is due to the ring
of radius r'
dE
II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9e8e39e4-529c-4b31-aa40-d9563f11aa5a%2Ffa953928-4d05-4ac9-9c34-348b143d1fef%2Fq52en9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:E,
dE
Q-AL
- L/2
+L/2
dx
(x0,0)
Figure 3:
E,
9(0.0.z)
Q-2xa A
Figure 4:
4. For a ring of radius a and uniform line density A the electric field f at position (0,0,z) is given by E, =
4re0(a2+z2)
daz
3.
2e0(a2+z2) 2
[see figure 4]. If a=10cm, A =
.015n C
then
(a) at z = 0, z = , z = , z =
2 and z = o the electric field is given as E, = 0, E = 1.67399 x 10° N/C,E,
= 2.17458 x 10 N/C,
%3D
2/2
Ez = 1.53766 × 106 N/C and E, = 0 respectively (True,False)
(b) At z = the electric field is maximum (True,False)
%3D
(c) The maximum force on a point charge q 1µC is F =
qEa) = 2.17458N (True,False)
%3D
E,
dE is due to the ring
of radius r'
dE
II
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