4. Find all local maxima and minima of the following function ƒ : R → R. Which ones are global maxima/minima? Explain. f(r) = 4 2p3 11 2 - 6x + 2 for all x E R.

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Chapter1: Functions And Models
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Please solve the screenshot and explain how you get the global max/min (in general). Thanks!

4. Find all local maxima and minima of the following function ƒ : R → R. Which ones are
global maxima/minima? Explain.
f(r) =
4
2p3
11 2
- 6x + 2 for all x E R.
Transcribed Image Text:4. Find all local maxima and minima of the following function ƒ : R → R. Which ones are global maxima/minima? Explain. f(r) = 4 2p3 11 2 - 6x + 2 for all x E R.
Expert Solution
Step 1

 Definition used - 

       Local maxima and minima -  In an open interval, Maximum and minimum value of the function is called local maxima and minima respectively.

      It can be found using first or second derivative tests.

      Second derivative test - First we equate the first derivative to 0 and solve for x. It gives us critical values of x at which local maxima or minima occur. Then we found the second derivative and plug critical values in it.

                         If f''(c)>0then there is a local minimum at x = c.

                         If f''(c)<0 then there is a local maximum at x =c.

    Global maxima or minima-  In a given interval, Maximum and minimum value of the function is called local maxima and minima respectively.

Step 2

   Given -     f(x)=x44-2x3+112x2-6x+2,  xR

                   Taking the derivative of it with respect to x both sides-

                   f'(x)=x3-6x2+11x-6

                   f'(x)=0

                   x3-6x2+11x-6=0

                    x=1,2,3

                   These are critical values.

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