4. Draw 1 card from a standard deck of 52. Let + = event that a spade turns up Red = event that a red card turns up 2 = the event that a 2 turns up Find the following: a. P(e ) 0.25 b. P(e or Red) 0.75 c. P(e or 2) 0.3077 d. P(* and Red) 0 e. Are the events • and Red disjoint? Yes f. P( and 2) 0.0192
4. Draw 1 card from a standard deck of 52. Let + = event that a spade turns up Red = event that a red card turns up 2 = the event that a 2 turns up Find the following: a. P(e ) 0.25 b. P(e or Red) 0.75 c. P(e or 2) 0.3077 d. P(* and Red) 0 e. Are the events • and Red disjoint? Yes f. P( and 2) 0.0192
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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This question is for practice and not graded.
![Refer to Question #4 on the pdf
4. Draw 1 card from a standard deck of 52.
Let a = event that a spade turns up
Red = event that a red card turns up
2 = the event that a 2 turns up
Find the following:
a. P(e ) 0.25
b. P(e or Red) 0.75
c. P(e or 2) 0.3077
d. P(e and Red)
e. Are the events e and Red disjoint? Yes
f. P(e and 2) 0.0192
g. Are the events + and 2 disjoint? No
h. P(* | Red ) 0.5
i. Are the events + and Red independent? Yes
j. P(* | 2) [ Select]
k. Are the events a and 2 independent? No
>
>](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F01e5e66e-0e79-4c86-85a9-0b0202abd934%2F8accda82-45c0-4c3f-8309-4cd2e9d946cf%2Fm61srh_processed.png&w=3840&q=75)
Transcribed Image Text:Refer to Question #4 on the pdf
4. Draw 1 card from a standard deck of 52.
Let a = event that a spade turns up
Red = event that a red card turns up
2 = the event that a 2 turns up
Find the following:
a. P(e ) 0.25
b. P(e or Red) 0.75
c. P(e or 2) 0.3077
d. P(e and Red)
e. Are the events e and Red disjoint? Yes
f. P(e and 2) 0.0192
g. Are the events + and 2 disjoint? No
h. P(* | Red ) 0.5
i. Are the events + and Red independent? Yes
j. P(* | 2) [ Select]
k. Are the events a and 2 independent? No
>
>
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