4. Design a low-pass filter circuit that has the transfer function. Assume all capacitors to be 0.1µF. Final answer should be a circuit. -6283 H¿(s) = (s + 628)(s² + 628s + 6282) Table 16.3-2 Denominators of Butterworth Low-Pass Filters with a Cutoff Frequency we = 1 rad/s ORDER DENOMINATOR, D(S) s+1 2+1414s +1 (s+1)(s? +s+ 1) 4 (2 +0.765s + 1)(s + 1.848s + 1) (s+ 1)(s +0.618s + 1)(s + 1.618s + 1) (s? +0.518s + 1)(s +1.414s + 1)(s + 1.932s +1) (s + 1)(s +0.445s + 1)(s + 1.247s+ 1)(s + 1.802s +1) 6. (s +0.390s + 1)3 +1.111s + 1)(s² + 1.663s + 1)(s? + 1.962s + 1) (s +1)(s +0.347s + 1)(s +s+1)( +1.532s + 1)(s?+ 1.879s + 1) (s?+0.313s + 1)(s? +0.908s + 1)(² + 1.414s + 1)(s? + 1.782s + 1)(s² +1.975s + 1) 8 9 10 Table 16.4-2 Sallen-Key Filters FILTER TYPE CIRCUIT DESIGN EQUATIONS RC Low-pass RC High pass A- 1DR RC Band-pass 2RS A- 1)R A AQ RC Band-stop (notch) A- IR
4. Design a low-pass filter circuit that has the transfer function. Assume all capacitors to be 0.1µF. Final answer should be a circuit. -6283 H¿(s) = (s + 628)(s² + 628s + 6282) Table 16.3-2 Denominators of Butterworth Low-Pass Filters with a Cutoff Frequency we = 1 rad/s ORDER DENOMINATOR, D(S) s+1 2+1414s +1 (s+1)(s? +s+ 1) 4 (2 +0.765s + 1)(s + 1.848s + 1) (s+ 1)(s +0.618s + 1)(s + 1.618s + 1) (s? +0.518s + 1)(s +1.414s + 1)(s + 1.932s +1) (s + 1)(s +0.445s + 1)(s + 1.247s+ 1)(s + 1.802s +1) 6. (s +0.390s + 1)3 +1.111s + 1)(s² + 1.663s + 1)(s? + 1.962s + 1) (s +1)(s +0.347s + 1)(s +s+1)( +1.532s + 1)(s?+ 1.879s + 1) (s?+0.313s + 1)(s? +0.908s + 1)(² + 1.414s + 1)(s? + 1.782s + 1)(s² +1.975s + 1) 8 9 10 Table 16.4-2 Sallen-Key Filters FILTER TYPE CIRCUIT DESIGN EQUATIONS RC Low-pass RC High pass A- 1DR RC Band-pass 2RS A- 1)R A AQ RC Band-stop (notch) A- IR
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Question
Can anyone help me with this circuits question
![4.
Design a low-pass filter circuit that has the transfer function. Assume all
capacitors to be 0.1µF. Final answer should be a circuit.
-6283
H¿(s) =
(s + 628)(s² + 628s + 628²)
Table 16.3-2 Denominators of Butterworth Low-Pass Filters with a Cutoff Frequency we = 1 rad/s
ORDER
DENOMINATOR, D(S)
s+1
2+1.414s +1
(s+ 1)(s² +s+ 1)
(s? +0.765s + 1)(s + 1.848s + 1)
3
4
(s+ 1)(s² + 0.618s + 1)(s² + 1.618s + 1)
(s? +0.518s + 1)(s² + 1.414s + 1)(s² + 1.932s + 1)
(s +1)(s? + 0.445s+ 1)(² + 1.247s+ 1)(s² + 1.802s +1)
(s +0.390s + 1)?+1.111s+ 1)(s² + 1.663s + 1)(s²+ 1.962s + 1)
(s +1)(s? +0.347s + 1)( +s+1)(² + 1.532s + 1)(s+ 1.879s + 1)
(s?+0.313s + 1)(s² + 0.908s + 1)(s² + 1.414s + 1)(s² + 1.782s + 1)(s² +1.975s + 1)
6.
7
8
9
10
Table 16.4-2 Sallen-Key Filters
FILTER TYPE
CIRCUIT
DESIGN EQUATIONS
RC
Low-pass
CA - 1IR
RC
High-pass
R2
A- DR
RC
Band-pass
2RS
A- 1DR
A AQ
RC
Band-stop (notch)
A- IN](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f6c81c7-9a41-4014-8916-60df888d5014%2F874619aa-1b6e-4615-a776-af3be0a788cd%2Faokkcof_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4.
Design a low-pass filter circuit that has the transfer function. Assume all
capacitors to be 0.1µF. Final answer should be a circuit.
-6283
H¿(s) =
(s + 628)(s² + 628s + 628²)
Table 16.3-2 Denominators of Butterworth Low-Pass Filters with a Cutoff Frequency we = 1 rad/s
ORDER
DENOMINATOR, D(S)
s+1
2+1.414s +1
(s+ 1)(s² +s+ 1)
(s? +0.765s + 1)(s + 1.848s + 1)
3
4
(s+ 1)(s² + 0.618s + 1)(s² + 1.618s + 1)
(s? +0.518s + 1)(s² + 1.414s + 1)(s² + 1.932s + 1)
(s +1)(s? + 0.445s+ 1)(² + 1.247s+ 1)(s² + 1.802s +1)
(s +0.390s + 1)?+1.111s+ 1)(s² + 1.663s + 1)(s²+ 1.962s + 1)
(s +1)(s? +0.347s + 1)( +s+1)(² + 1.532s + 1)(s+ 1.879s + 1)
(s?+0.313s + 1)(s² + 0.908s + 1)(s² + 1.414s + 1)(s² + 1.782s + 1)(s² +1.975s + 1)
6.
7
8
9
10
Table 16.4-2 Sallen-Key Filters
FILTER TYPE
CIRCUIT
DESIGN EQUATIONS
RC
Low-pass
CA - 1IR
RC
High-pass
R2
A- DR
RC
Band-pass
2RS
A- 1DR
A AQ
RC
Band-stop (notch)
A- IN
![Table 16.5-2 First-Order Filter Stages
FILTER TYPE
FIRST ORDER CIRCUIT
DESIGN EQUATION
HG) =+P
where
1
p=
R2C
Reminder!
R1
R2
Low-pass
in this table
and
for the low
RC
pass filter k
is not the
gain of this
filter as it is
R1
R2
where
1
p=
RC
High-pass
and
R2
in other
R1
tables.
Table 14.2-1 Laplace Transform Pairs
f(t) for t>0
F(s) = L[f(1}u(t)}
8(4)
1
1
u(t)
1
e-at
s+a
1
n!
n!
(s + a)"+1
sin (ot)
s2 + w2
cos (wt)
s2 + w2
at
e
sin (@t)
(s +a)? + w2
s+a
e-at cos (wt)
(s + a)? + w?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f6c81c7-9a41-4014-8916-60df888d5014%2F874619aa-1b6e-4615-a776-af3be0a788cd%2Fy2ke8wq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Table 16.5-2 First-Order Filter Stages
FILTER TYPE
FIRST ORDER CIRCUIT
DESIGN EQUATION
HG) =+P
where
1
p=
R2C
Reminder!
R1
R2
Low-pass
in this table
and
for the low
RC
pass filter k
is not the
gain of this
filter as it is
R1
R2
where
1
p=
RC
High-pass
and
R2
in other
R1
tables.
Table 14.2-1 Laplace Transform Pairs
f(t) for t>0
F(s) = L[f(1}u(t)}
8(4)
1
1
u(t)
1
e-at
s+a
1
n!
n!
(s + a)"+1
sin (ot)
s2 + w2
cos (wt)
s2 + w2
at
e
sin (@t)
(s +a)? + w2
s+a
e-at cos (wt)
(s + a)? + w?
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