4. Dave has a lawn mowing business. Based on daily sales figures for the past two summers, he has developed the following probability distribution for X = number of lawns mowed on a randomly selected day. Number of Lawns xi Probability pi a. Describe P(X > 0) in words and find its value. 0 0.2 c. Describe the shape of the distribution. 1 0.4 b. Express the event "mows at most one lawn" in terms of X and find its probability. b. Calculate and interpret the mean of C. 2 0.3 3 0.1 d. Determine the mean and standard deviation for the distribution of lawns mowed. c. Calculate and interpret the standard deviation of C. 5. All of Dave's customers are neighbors that have yards of about the same size. Dave charges a flat rate of $32 for mowing and trimming and $20 for just mowing. Based on experience, he determines that the probability that a randomly selected customer wants him to mow and trim the lawn is 0.85; the rest of his customers just want him to mow. Let C = the amount Dave charges a randomly selected customer. a. Make a table that shows the probability distribution of C.

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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4.
Dave has a lawn mowing business. Based on daily sales figures for the past two summers, he has
developed the following probability distribution for X = number of lawns mowed on a randomly
selected day.
Number of Lawns xi
Probability pi
a. Describe P(X > 0) in words and find its value.
0
0.2
c. Describe the shape of the distribution.
1
0.4
b. Express the event "mows at most one lawn" in terms of X and find its probability.
b. Calculate and interpret the mean of C.
2
0.3
3
0.1
d. Determine the mean and standard deviation for the distribution of lawns mowed.
c. Calculate and interpret the standard deviation of C.
5. All of Dave's customers are neighbors that have yards of about the same size. Dave charges a flat rate
of $32 for mowing and trimming and $20 for just mowing. Based on experience, he determines that
the probability that a randomly selected customer wants him to mow and trim the lawn is 0.85; the
rest of his customers just want him to mow.
Let C = the amount Dave charges a randomly selected customer.
a. Make a table that shows the probability distribution of C.
Transcribed Image Text:4. Dave has a lawn mowing business. Based on daily sales figures for the past two summers, he has developed the following probability distribution for X = number of lawns mowed on a randomly selected day. Number of Lawns xi Probability pi a. Describe P(X > 0) in words and find its value. 0 0.2 c. Describe the shape of the distribution. 1 0.4 b. Express the event "mows at most one lawn" in terms of X and find its probability. b. Calculate and interpret the mean of C. 2 0.3 3 0.1 d. Determine the mean and standard deviation for the distribution of lawns mowed. c. Calculate and interpret the standard deviation of C. 5. All of Dave's customers are neighbors that have yards of about the same size. Dave charges a flat rate of $32 for mowing and trimming and $20 for just mowing. Based on experience, he determines that the probability that a randomly selected customer wants him to mow and trim the lawn is 0.85; the rest of his customers just want him to mow. Let C = the amount Dave charges a randomly selected customer. a. Make a table that shows the probability distribution of C.
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