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4. Complete the following statement: Resulting from the alpha decay of (A)-223 is a daughter nuclide with (B) neutrons and 71 protons. (A) = Ta, (B) = 219 %3! (A) = Ta, (B) = 148 (A) = Tm, (B) = 219 %3! (A) = Tm, (B) = 148 %3D

4. Complete the following statement: Resulting from the alpha decay of (A)-223 is a daughter nuclide with (B) neutrons and 71 protons. (A) = Ta, (B) = 219 %3! (A) = Ta, (B) = 148 (A) = Tm, (B) = 219 %3! (A) = Tm, (B) = 148 %3D

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter21: Nuclear Chemistry
Section: Chapter Questions
Problem 21.22QE
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4. Complete the following statement: Resulting from the alpha decay of (A)-223 is a daughter nuclide with (B) neutrons and 71 protons. (A) = Ta, (B) = 219 %3D (A) = Ta, (B) = 148 %3! (A) = Tm, (B) = 219 %3! (A) = Tm, (B) = 148 %3D
Transcribed Image Text:4. Complete the following statement: Resulting from the alpha decay of (A)-223 is a daughter nuclide with (B) neutrons and 71 protons. (A) = Ta, (B) = 219 %3D (A) = Ta, (B) = 148 %3! (A) = Tm, (B) = 219 %3! (A) = Tm, (B) = 148 %3D
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