You have obtained experimental kinetic data for two versions of the same enzyme, a wild-type and a mutant differing from the wild-type at a single amino acid. The data are given in the table. Wild-type Mutant max (μmol min Vo 100 1 Compare the kinetic parameters of the two versions using the data in the table. = KM (mm) 10 0.1 Assuming a two-step reaction scheme in which k_₁ is much larger than k2, which of the following statements are correct? Calculate the initial velocity of the reaction catalyzed by the wild-type enzyme when the substrate concentration is 10 mm. The mutant version has a higher affinity for the substrate. The wild-type version has a higher affinity for the substrate. The mutant version requires a greater concentration of substrate to achieve Vmax. The wild-type version requires a greater concentration of substrate to achieve Vmax. μmol min¹
You have obtained experimental kinetic data for two versions of the same enzyme, a wild-type and a mutant differing from the wild-type at a single amino acid. The data are given in the table. Wild-type Mutant max (μmol min Vo 100 1 Compare the kinetic parameters of the two versions using the data in the table. = KM (mm) 10 0.1 Assuming a two-step reaction scheme in which k_₁ is much larger than k2, which of the following statements are correct? Calculate the initial velocity of the reaction catalyzed by the wild-type enzyme when the substrate concentration is 10 mm. The mutant version has a higher affinity for the substrate. The wild-type version has a higher affinity for the substrate. The mutant version requires a greater concentration of substrate to achieve Vmax. The wild-type version requires a greater concentration of substrate to achieve Vmax. μmol min¹
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Concept explainers
Catalysis and Enzymatic Reactions
Catalysis is the kind of chemical reaction in which the rate (speed) of a reaction is enhanced by the catalyst which is not consumed during the process of reaction and afterward it is removed when the catalyst is not used to make up the impurity in the product. The enzymatic reaction is the reaction that is catalyzed via enzymes.
Lock And Key Model
The lock-and-key model is used to describe the catalytic enzyme activity, based on the interaction between enzyme and substrate. This model considers the lock as an enzyme and the key as a substrate to explain this model. The concept of how a unique distinct key only can have the access to open a particular lock resembles how the specific substrate can only fit into the particular active site of the enzyme. This is significant in understanding the intermolecular interaction between proteins and plays a vital role in drug interaction.
Question
C7 Q7:
Transcribed Image Text:You have obtained experimental kinetic data for two versions of the same enzyme, a wild-type and a mutant differing from the
wild-type at a single amino acid. The data are given in the table.
Wild-type
Mutant
Vmax
(μmol min
100
1
Vo =
Compare the kinetic parameters of the two versions using the data in the table.
Assuming a two-step reaction scheme in which k_₁ is much larger than k2, which of the following statements are correct?
KM
(mm)
10
0.1
The mutant version has a higher affinity for the substrate.
The wild-type version has a higher affinity for the substrate.
The mutant version requires a greater concentration of substrate to achieve Vmax -
The wild-type version requires a greater concentration of substrate to achieve Vmax.
Calculate the initial velocity of the reaction catalyzed by the wild-type enzyme when the substrate concentration is 10 mM.
neither version.
The reaction equilibrium is reached once there is no net change in the concentration of the substrate or the product.
Based on the data table and your initial velocity calculation, the reaction equilibrium is altered more in the direction of the
product by
both versions.
the mutant version.
μmol min-¹
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 3 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY