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4. Calculate AH for the reaction CH. (g) + NHs (g)-HCN (g) + 3 H₂ (g), from the reactions. N₂ (g) + 3 H: (g)-2 NH₂ (g) C (s, graphite) + 2 H₂(g) → CH. (g) H() +2C (s, graphite) + N₂ (g) - 2 HCN (g) AH--91.8 kJ AH -74.9 kJ/mole AH- +270.3 kJ

4. Calculate AH for the reaction CH. (g) + NHs (g)-HCN (g) + 3 H₂ (g), from the reactions. N₂ (g) + 3 H: (g)-2 NH₂ (g) C (s, graphite) + 2 H₂(g) → CH. (g) H() +2C (s, graphite) + N₂ (g) - 2 HCN (g) AH--91.8 kJ AH -74.9 kJ/mole AH- +270.3 kJ

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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4. Calculate AH for the reaction CH. (g) + NH, (g) - HCN (g) + 3 H₂ (g), from the reactions. N₂ (g) + 3 H₂(g) → 2 NH₂ (g) AH--91.8 kJ C (s, graphite) + 2 H₂(g) - CH4 (g) H: (g) + 2 C (s, graphite) + N₂ (g) → 2 HCN (g) AH -74.9 kJ/mole AH-+270.3 kJ 5. Calculate AH for the reaction 2 Al (s) + 3 Cl2 (g) - 2 AlCl3 (s) from the following data. 2 Al (s) + 6 HCl (aq)-2 AICI, (aq) + 3 H₂ (g) AH=-1049. kJ HC1 (g) → HCl (aq) H₂ (g) + Cl₂ (g) → 2 HCl (g) AICI3 (s)-AICI, (aq) AH-74.8 kJ/mole AH=-1845. kJ AH-323. kJ/mole 3. Find AH for acetic acid, 2 C(s, graphite) + 2 H₂ (g) + O₂(g) → HC₂H₂O₂ (1), using the following thermochemical data. HCHO(l)+20 (g)-2 CO (g)+2HO(l) C (s, graphite) + O₂(g) - CO₂ (g) H₂(g) + 1/2 O2 (g) → H₂O (1) AH -875. kJ/mole AH--394.51 kJ/mole AH -285.8 kJ/mole
Transcribed Image Text:4. Calculate AH for the reaction CH. (g) + NH, (g) - HCN (g) + 3 H₂ (g), from the reactions. N₂ (g) + 3 H₂(g) → 2 NH₂ (g) AH--91.8 kJ C (s, graphite) + 2 H₂(g) - CH4 (g) H: (g) + 2 C (s, graphite) + N₂ (g) → 2 HCN (g) AH -74.9 kJ/mole AH-+270.3 kJ 5. Calculate AH for the reaction 2 Al (s) + 3 Cl2 (g) - 2 AlCl3 (s) from the following data. 2 Al (s) + 6 HCl (aq)-2 AICI, (aq) + 3 H₂ (g) AH=-1049. kJ HC1 (g) → HCl (aq) H₂ (g) + Cl₂ (g) → 2 HCl (g) AICI3 (s)-AICI, (aq) AH-74.8 kJ/mole AH=-1845. kJ AH-323. kJ/mole 3. Find AH for acetic acid, 2 C(s, graphite) + 2 H₂ (g) + O₂(g) → HC₂H₂O₂ (1), using the following thermochemical data. HCHO(l)+20 (g)-2 CO (g)+2HO(l) C (s, graphite) + O₂(g) - CO₂ (g) H₂(g) + 1/2 O2 (g) → H₂O (1) AH -875. kJ/mole AH--394.51 kJ/mole AH -285.8 kJ/mole
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