4. At 1000 K, 0.3 % of 1 mol of I, dissociates to establish the equilibrium represented by the equation, 2 (g) 2 21 (g), in one liter container. The value of Ke at 1000 K is: A) 3.6 x 10-5 D) 6.0 x 10 -5 B) 6.0 x 10-3 C) 3.7 x 10-3 E) 2.8 x 10 -3

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4. At 1000 K, 0.3 % of 1 mol ofL dissociates to
establish the equilibrium represented by the equation,
I2 (g) 2 21 (g), in one liter container. The value
of Ke at 1000 K is:
A) 3.6 x 105
B) 6.0 x 10-3
C) 3.7 x 10-3
D) 6.0 x 10 -5
E) 2.8 x 10 -3
Transcribed Image Text:4. At 1000 K, 0.3 % of 1 mol ofL dissociates to establish the equilibrium represented by the equation, I2 (g) 2 21 (g), in one liter container. The value of Ke at 1000 K is: A) 3.6 x 105 B) 6.0 x 10-3 C) 3.7 x 10-3 D) 6.0 x 10 -5 E) 2.8 x 10 -3
mass (g)
reac
re inside
6.0
2.
Calculate
CO
5.1
4.2
ct to pi
3.0
CO,
1.1
codss
time
The figure shows the establishment of equilibrium
for C (s) + CO, (g) 200 (g) at a certain tem-
perature in a one liter container. The value of K. for
this reaction is : (C= 12, CO, = 44, CO = 28)
A) 3.14 B) 16.0 C) 0.90 D) 2.12 E) 6.00
Transcribed Image Text:mass (g) reac re inside 6.0 2. Calculate CO 5.1 4.2 ct to pi 3.0 CO, 1.1 codss time The figure shows the establishment of equilibrium for C (s) + CO, (g) 200 (g) at a certain tem- perature in a one liter container. The value of K. for this reaction is : (C= 12, CO, = 44, CO = 28) A) 3.14 B) 16.0 C) 0.90 D) 2.12 E) 6.00
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