4. Arrange the following bonds in order of increasing polarity: C-O, C-C, C-N, C-F A. C-O< C-C < C-N < C-F B. C-N

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Chapter1: Chemical Foundations
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**Exercise: Ordering Chemical Bonds by Polarity**

**Question:**
Arrange the following bonds in order of increasing polarity: C-O, C-C, C-N, C-F.

**Options:**

A. C-O < C-C < C-N < C-F  
B. C-N < C-O < C-C < C-F  
C. C-F < C-O < C-N < C-C  
D. C-C < C-N < C-O < C-F  
E. C-C < C-O < C-N < C-F  

**Correct Answer:**
Option D is circled as the correct answer, indicating the order: C-C < C-N < C-O < C-F. 

**Explanation:**
This exercise asks students to assess the polarity of different chemical bonds. Polarity is determined by the difference in electronegativity between atoms. The larger the difference, the more polar the bond. In the provided options, the order D reflects the increasing polarity based on common electronegativity values, with fluorine being the most electronegative.
Transcribed Image Text:**Exercise: Ordering Chemical Bonds by Polarity** **Question:** Arrange the following bonds in order of increasing polarity: C-O, C-C, C-N, C-F. **Options:** A. C-O < C-C < C-N < C-F B. C-N < C-O < C-C < C-F C. C-F < C-O < C-N < C-C D. C-C < C-N < C-O < C-F E. C-C < C-O < C-N < C-F **Correct Answer:** Option D is circled as the correct answer, indicating the order: C-C < C-N < C-O < C-F. **Explanation:** This exercise asks students to assess the polarity of different chemical bonds. Polarity is determined by the difference in electronegativity between atoms. The larger the difference, the more polar the bond. In the provided options, the order D reflects the increasing polarity based on common electronegativity values, with fluorine being the most electronegative.
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