4. Another function whose graph has a similar shape to the graphs in question 3 is ket f(t) (1+ et)² where k is a fixed constant. (a) A sketch of the graph of f is given below. Showing all your working, find the coordinates of the turning point on the graph if k = 1500. (b) Find the general antiderivative F(t) of f(t), i.e. calculate | f(t) dt with k = 1500. (c) Your formula for F(t) will have a general constant C. Choose the value(s) for C so that the graph of F(t) looks like the sketch below, with horizontal asymptotes y = 0 and y = 1500. (d) By simplifying the right-hand side of the equation, show that 1 f(t) = F(t)(1500 – F(t)). 1500

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
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Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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Can you help me with 4.(d) please?

4. Another function whose graph has a similar shape to the graphs in question 3 is
ket
f(t)
(1+ et)²
where k is a fixed constant.
(a) A sketch of the graph of f is given below.
Showing all your working, find the coordinates of the turning point on the graph if
k = 1500.
(b) Find the general antiderivative F(t) of f(t), i.e. calculate
| f(t) dt with k = 1500.
(c) Your formula for F(t) will have a general constant C. Choose the value(s) for C so
that the graph of F(t) looks like the sketch below, with horizontal asymptotes y = 0
and y = 1500.
(d) By simplifying the right-hand side of the equation, show that
1
f(t) =
F(t)(1500 – F(t)).
1500
Transcribed Image Text:4. Another function whose graph has a similar shape to the graphs in question 3 is ket f(t) (1+ et)² where k is a fixed constant. (a) A sketch of the graph of f is given below. Showing all your working, find the coordinates of the turning point on the graph if k = 1500. (b) Find the general antiderivative F(t) of f(t), i.e. calculate | f(t) dt with k = 1500. (c) Your formula for F(t) will have a general constant C. Choose the value(s) for C so that the graph of F(t) looks like the sketch below, with horizontal asymptotes y = 0 and y = 1500. (d) By simplifying the right-hand side of the equation, show that 1 f(t) = F(t)(1500 – F(t)). 1500
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