4. An object is 30 cm from a thin, positive lens. The focal length of the lens is 10 cm. Where will the image be formed by this positive lens? I O d= 9 = Is the image real of imaginary? Mark the position of this image on the figure. 5. There is a negative lens to the right of the positive lens, at a distance of L= 10 cm away. What is the distance between this negative lens and the image formed by the positive lens? 30 cm p= 6. The image formed by the positive lens is the object of the negative lens. Is the image formed by the positive lens to the right or the left of the negative lens? In this case, is the object distance positive or negative? To the negative lens, 7. The focal length of the negative lens is also 10 cm (negative). Calculate where the image will be formed by the negative lens. 9= mark the position of this image on the figure. Is the image real or virtual? For a diverging lens, the focal length is negative by definition. Thus in the thin lens equation, if the object distance is positive, then the image distance will always be negative. How did we make the diverging lens to form a real image?
Ray Optics
Optics is the study of light in the field of physics. It refers to the study and properties of light. Optical phenomena can be classified into three categories: ray optics, wave optics, and quantum optics. Geometrical optics, also known as ray optics, is an optics model that explains light propagation using rays. In an optical device, a ray is a direction along which light energy is transmitted from one point to another. Geometric optics assumes that waves (rays) move in straight lines before they reach a surface. When a ray collides with a surface, it can bounce back (reflect) or bend (refract), but it continues in a straight line. The laws of reflection and refraction are the fundamental laws of geometrical optics. Light is an electromagnetic wave with a wavelength that falls within the visible spectrum.
Converging Lens
Converging lens, also known as a convex lens, is thinner at the upper and lower edges and thicker at the center. The edges are curved outwards. This lens can converge a beam of parallel rays of light that is coming from outside and focus it on a point on the other side of the lens.
Plano-Convex Lens
To understand the topic well we will first break down the name of the topic, ‘Plano Convex lens’ into three separate words and look at them individually.
Lateral Magnification
In very simple terms, the same object can be viewed in enlarged versions of itself, which we call magnification. To rephrase, magnification is the ability to enlarge the image of an object without physically altering its dimensions and structure. This process is mainly done to get an even more detailed view of the object by scaling up the image. A lot of daily life examples for this can be the use of magnifying glasses, projectors, and microscopes in laboratories. This plays a vital role in the fields of research and development and to some extent even our daily lives; our daily activity of magnifying images and texts on our mobile screen for a better look is nothing other than magnification.
need problems 4, 5, 6, and 7 if possible, please show work, thank you.
![**Course # _____________ Section # _____________ Name _____________________**
**4.** An object is 30 cm from a thin, positive lens. The focal length of the lens is 10 cm. Where will the image be formed by this positive lens?
[Diagram of a lens system]
O [object] 30 cm |---| L |---| [lens system with two lenses, one positive and one negative]
*q = ___________*
Is the image real or imaginary?
Mark the position of this image on the figure.
**5.** There is a negative lens to the right of the positive lens, at a distance of *L = 10 cm* away. What is the distance between this negative lens and the image formed by the positive lens?
*d = ___________*
**6.** The image formed by the positive lens is the object of the negative lens. Is the image formed by the positive lens to the right or the left of the negative lens? In this case, is the object distance positive or negative?
To the negative lens,
*p = ___________*
**7.** The focal length of the negative lens is also 10 cm (negative). Calculate where the image will be formed by the negative lens.
*q = ___________*
Mark the position of this image on the figure. Is the image real or virtual?
For a diverging lens, the focal length is negative by definition. Thus in the thin lens equation, if the object distance is positive, then the image distance will always be negative. How did we make the diverging lens to form a real image?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F77d2f4c8-4183-4052-877b-b5f84c5df55f%2Fded5af64-350d-4c39-922b-9a5878dc3528%2Fictlhjv_processed.jpeg&w=3840&q=75)
Step by step
Solved in 3 steps with 3 images
