4. Ammonium carbonate (NH4)2CO3 is a white solid that decomposes with heat. It has many uses, like as a component in baking powder and fire extinguishers. What is the percentage composition of ammonium carbonate and how many moles are in 41.6 g of Ammonium carbonate? *Please follow the given format: Given in the problem: Solution: Final answer: e.g. Element: Atomic No. of Molar mass atom: 45.98 g/mol mass: 45.98 -x100%-43.38% 105.99 12.01 -x100% = 11.33% 105.99 48.00 -x100% = 45.29% Na 22.99 amu 2 NazCO3 C 1 12.01 g/mol 12.01 amu 16.00 amu 48.00 g/mol Total: 105.99 g/mol 3 105.99 Total: 100% Given in the Solution: Final problem: answer: Element: Atomic No. of Molar mass atom: mass: Total: Total: 100% Calculate the no. of moles
4. Ammonium carbonate (NH4)2CO3 is a white solid that decomposes with heat. It has many uses, like as a component in baking powder and fire extinguishers. What is the percentage composition of ammonium carbonate and how many moles are in 41.6 g of Ammonium carbonate? *Please follow the given format: Given in the problem: Solution: Final answer: e.g. Element: Atomic No. of Molar mass atom: 45.98 g/mol mass: 45.98 -x100%-43.38% 105.99 12.01 -x100% = 11.33% 105.99 48.00 -x100% = 45.29% Na 22.99 amu 2 NazCO3 C 1 12.01 g/mol 12.01 amu 16.00 amu 48.00 g/mol Total: 105.99 g/mol 3 105.99 Total: 100% Given in the Solution: Final problem: answer: Element: Atomic No. of Molar mass atom: mass: Total: Total: 100% Calculate the no. of moles
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:4. Ammonium carbonate (NH4)2CO3 is a white solid that decomposes with heat. It has many uses, like as a
component in baking powder and fire extinguishers. What is the percentage composition of ammonium
carbonate and how many moles are in 41.6 g of Ammonium carbonate?
*Please follow the given format:
Given in the
problem:
Solution:
Final
answer:
e.g.
Element:
Atomic
No. of
Molar mass
mass:
atom:
45.98 g/mol
45.98
-x100%=43.38%
105.99
12.01
-x100% = 11.33%
105.99
48.00
x100% = 45.29%
Na
22.99 amu
2
NazCO3
C
1
12.01 g/mol
12.01 amu
16.00 amu
3
48.00 g/mol
105.99
Total:
Total: 100%
105.99 g/mol
Given in the
Solution:
Final
problem:
answer:
Element:
Atomic
No. of
Molar mass
atom:
mass:
Total:
Total: 100%
Calculate the no. of moles
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