4. A uniform electric field of magnitude E=435 N/C makes an angle of 0=65° with a palne surface of area A=3.5 m as in the figure. Find the electric flux through this surface.

Q: A uniform electric field E = 750 N/C passing through a flat square area A =10 square meters.…

A: Given: Electric field E = 750 NC Area A = 10 m2 To determine: Electric flux ϕE Formula used:…

Q: hat is the radius of a flat circle when it is placed in a uniform electric field magnitude of 4.6 x…

A: Given data- E=4.6 x 102 N/C ϕ=Electric flux=74.49Nm2/C θ=450 A=area of flat circle=πR2 R=radius of…

Q: 3. A solid insulating sphere with a radius a = 45cm carries a total net charge Q = 2.5x10-¹0C. Find…

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Q: In the figure shown, the magnitude of the uniform electric field is °E= 70 kN/C. Calculate the…

A: The electric flux Ø (in Nm2/C) , is given by                                    Ø = E.A…

Q: 2.An insulating sphere with a radius of 20 cm carries a uniform volume charge density of 1.5 x 10-6…

A: The total charge is given by, Here, ρ and V represents the volume charge density and the volume of…

Q: An electric field E = (-2+x²)N/Cî passes through a cube of side a = 2m as shown in the figure. Find…

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Q: 2. An electric field given by E = 6.1 i - 2.9(y? + 5.1) j pierces the Gaussian cube o edge length…

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Q: A uniform electric field E = 5000 N/C is passing through a flat square area A= 2m2 . Determine the…

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Q: a. Calculate the net enclosed charge by the Gaussian surface of radius r=20m. b. Electric field at…

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: A 3.0 cm diameter circle lies in yz -plane with unit area vector pointing in x-direction. What is…

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Q: hollow conducting sphere of radius 0.12 meters has a uniform charge distributed on its surface. The…

A: Given: radius (R) = 0.12 m distance (r) = 0.20 m  Electric field (E) = -10 N/C

Q: he electric flux (Φ) that passes through this surface

A: we know electric flux ϕ = E·A =EAcosθ where θ= angle between electric field and area vector A = area…

Q: The surface shown is a square and has a side length of 15.0 cm. The electric field acting on this…

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Q: What magnitude point charge (in C) creates a 10,000 N/C electric field at a distance of 0.200 m? How…

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Q: The following diagram shows a solid insulating sphere with a radius "a" and a charge +30 surrounded…

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Q: Question 2: Calculating Flux What is the electric flux through the surface shown in the figures…

A: We are given electric field through closed surfaces. We are also given the angle of these fields. We…

Q: 4. A uniform electric field of magnitude 19000 N/C is perpendicular to a square sheet with sides 0.7…

A: Given E= 19000N/C Side of square= 0.7m So A= 0.49m2 Electric Flux= E.A Cosx here E is electric field…

Q: 4. A surface has the area vector A=(4î +5j)m² . What is the flux of a uniform electric field through…

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Q: In Fig. 1, a butterfly net is in a uniform electric field of magnitude E =3.0 mN/C. The rim, a…

A: Electric field, E = 3×10-3 N/CRadius, a = 0.11 m Area, A = πa2A = π × 0.112A = 0.038 m2

Q: flat surface of area 3.10 m² is rotated in a uniform electric field of magnitude E = 6.65 x 105 N/C.…

A: Area, A = 3.1 m²Field, E = 6.65×10⁵ N/C

Q: The figure below shows a uniform electric field of magnitude E = 420 N/C making an angle of o =…

A: We need to find the angle between the normal to the plane and the electric field, then we will be…

Q: 2. A disk of radius 196 mm is oriented with its normal unit vector în at 60° to a uniform electric…

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Q: 10. A flat sheet of paper of area 0.830 m² is oriented so that the normal to the sheet is at an…

A: Answer:-  Given,  Area of a flat sheet of paper (A)=0.830 m2                              Angle…

Q: 3. A uniform electric fieldE = 8000 N/C passing through a flat square area A 1o m2. Determine the…

A: Given data:  Electric field (E) = 8000 N/C Area (A) = 10 m2 Required: Electric flux (Φ)

Q: b. 60 An object having the shape of a rectangular prism is placed in a uniform electrie field with…

A: Given, Electric field, E = 100 N/C and sides of cube are, a = 2mb = 3mc = 5m 1st calculating flux…

Q: A uniform electric field of magnitude 2.7 x 10* N/C is perpendicular to a square sheet with sides…

A: Given E=2.7×104N/C (Electric field) a=2.5m(side of square) A=a×a=2.5×2.5=6.25m2 (Area of the square…

Q: In a symmetrical electric field of 58.3 x 10, a flat circle with a diameter of 30 cm is C'…

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Q: Calculate the electric flux through the vertical rectangular surface of the box.

A: ●Magnitude of electric field, E = 8.26 ×104 N/C. ●Area of vertical rectangular surface of box, A =…