4. A thin, uniformly charged rod of length L, carrying total charge Q, lies on the x axis between x = 0 and x= L. Starting from E = S ke d ↑ , derive an expression for the electric field at the point (3L, 0) on the x axis. Use x as the integration variable, and include the following steps: a) draw the charge element dq, the vector r and the field element dĒ (produced by dq) on the diagram; b) express the integrand in terms of x, and do the integral; c) simplify the expression, writing the answer in terms of Q and L. %3D y 3L L
4. A thin, uniformly charged rod of length L, carrying total charge Q, lies on the x axis between x = 0 and x= L. Starting from E = S ke d ↑ , derive an expression for the electric field at the point (3L, 0) on the x axis. Use x as the integration variable, and include the following steps: a) draw the charge element dq, the vector r and the field element dĒ (produced by dq) on the diagram; b) express the integrand in terms of x, and do the integral; c) simplify the expression, writing the answer in terms of Q and L. %3D y 3L L
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Transcribed Image Text:4. A thin, uniformly charged rod of length L, carrying total charge Q, lies on the x axis between x = 0 and x = L.
Starting from E =
the integration variable, and include the following steps:
a) draw the charge element dq, the vector r and the field element dE (produced by dq) on the diagram;
b) express the integrand in terms of x, and do the integral;
c) simplify the expression, writing the answer in terms of Q and L.
S ke
dq
î, derive an expression for the electric field at the point (3L, 0) on the x axis. Use x as
r2
y
3L
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