4. A sleeve of mass M = 10 kg can slide on a horizontal frictionless rod. A block of mass m = 2.0 kg is suspended at the mid-point of a light inextensible cord of length 1= 102.5 cm, one end of which is attached to the sleeve and the ther to one end of the rod. Initially the sleeve is held at rest and the angle between the rod and a cord segment is 63 = sin (0.8) as show. in the figure. If a constant horizontal force F= 50 N is applied on the sieeve, find its speed when the angle between cord segments and the rod becomes 0= sin !(0.6)? m/e
4. A sleeve of mass M = 10 kg can slide on a horizontal frictionless rod. A block of mass m = 2.0 kg is suspended at the mid-point of a light inextensible cord of length 1= 102.5 cm, one end of which is attached to the sleeve and the ther to one end of the rod. Initially the sleeve is held at rest and the angle between the rod and a cord segment is 63 = sin (0.8) as show. in the figure. If a constant horizontal force F= 50 N is applied on the sieeve, find its speed when the angle between cord segments and the rod becomes 0= sin !(0.6)? m/e
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:F
4. A sleeve of mass M = 10 kg can slide on a horizontal frictionless rod. A
block of mass m = 2.0 kg is suspended at the mid-point of a light
inextensible cord of length 1 102.5 cm, one end of which is attached to
the sleeve and the ther to one end of the rod. Initially the sleeve is held
at rest and the angle between the rod and a cord segment is = 6 =
sin (0.8) as show. in the figure. If a constant horizontal force F= 50 N
is applied on the sieeve, find its speed when the angle between cord
segments and the rod becomes 0 = sin (0.6)?
Ans:41[2F Ccos8-Costo)
Ans: 2FCcos& -costo) - mg (sinto -Sind -12m/
5. In the arrangement shownthe middfe ock is initially held at rest
1.
MAmcase
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