4. A) Relate the rate of decomposition of N,0, to the rate of formation of NO, for the following reaction in a mathematical equation. 2N,O 5 - 4NO + O B) If the rate of decomposition of N,O, is 0.484 mol/liter.Sec, what is the rate of formation of NO,? (5 points)
4. A) Relate the rate of decomposition of N,0, to the rate of formation of NO, for the following reaction in a mathematical equation. 2N,O 5 - 4NO + O B) If the rate of decomposition of N,O, is 0.484 mol/liter.Sec, what is the rate of formation of NO,? (5 points)
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.70PAE: The label on a bottle of 3% (by volume) hydrogen peroxide, H2O2, purchased at a grocery store,...
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![**Problem 4: Chemical Reaction Rate Analysis**
**A) Relate the rate of decomposition of \( N_2O_5 \) to the rate of formation of \( NO_2 \) for the following reaction in a mathematical equation.**
\[ 2N_2O_5(g) \leftrightarrows 4NO_2(g) + O_2(g) \]
**B) If the rate of decomposition of \( N_2O_5 \) is \( 0.484 \, \text{mol/L·s} \), what is the rate of formation of \( NO_2 \)?** (5 points)
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### Explanation:
**Part A:**
To relate the rate of decomposition of \( N_2O_5 \) to the rate of formation of \( NO_2 \), we need to use the stoichiometry of the reaction.
Given the reaction:
\[ 2N_2O_5(g) \leftrightarrows 4NO_2(g) + O_2(g) \]
The equation indicates that 2 moles of \( N_2O_5 \) decompose to produce 4 moles of \( NO_2 \).
Therefore, the rate of formation of \( NO_2 \) (\( \text{rate}_{NO_2} \)) is twice the rate of decomposition of \( N_2O_5 \) (\( \text{rate}_{N_2O_5} \)).
Mathematically, this relationship can be described as:
\[ \text{rate}_{NO_2} = 2 \times \text{rate}_{N_2O_5} \]
**Part B:**
We are given the rate of decomposition of \( N_2O_5 \):
\[ \text{rate}_{N_2O_5} = 0.484 \, \text{mol/L·s} \]
Using the relationship from Part A:
\[ \text{rate}_{NO_2} = 2 \times 0.484 \, \text{mol/L·s} \]
\[ \text{rate}_{NO_2} = 0.968 \, \text{mol/L·s} \]
Thus, the rate of formation of \( NO_2 \) is \( 0.968 \, \text{mol/L·s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdf5aa2e5-f0b0-4839-a4ef-6f98d6dc8551%2F8de490ac-0723-455c-9566-51db0e3317bf%2F94qn76d_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem 4: Chemical Reaction Rate Analysis**
**A) Relate the rate of decomposition of \( N_2O_5 \) to the rate of formation of \( NO_2 \) for the following reaction in a mathematical equation.**
\[ 2N_2O_5(g) \leftrightarrows 4NO_2(g) + O_2(g) \]
**B) If the rate of decomposition of \( N_2O_5 \) is \( 0.484 \, \text{mol/L·s} \), what is the rate of formation of \( NO_2 \)?** (5 points)
---
### Explanation:
**Part A:**
To relate the rate of decomposition of \( N_2O_5 \) to the rate of formation of \( NO_2 \), we need to use the stoichiometry of the reaction.
Given the reaction:
\[ 2N_2O_5(g) \leftrightarrows 4NO_2(g) + O_2(g) \]
The equation indicates that 2 moles of \( N_2O_5 \) decompose to produce 4 moles of \( NO_2 \).
Therefore, the rate of formation of \( NO_2 \) (\( \text{rate}_{NO_2} \)) is twice the rate of decomposition of \( N_2O_5 \) (\( \text{rate}_{N_2O_5} \)).
Mathematically, this relationship can be described as:
\[ \text{rate}_{NO_2} = 2 \times \text{rate}_{N_2O_5} \]
**Part B:**
We are given the rate of decomposition of \( N_2O_5 \):
\[ \text{rate}_{N_2O_5} = 0.484 \, \text{mol/L·s} \]
Using the relationship from Part A:
\[ \text{rate}_{NO_2} = 2 \times 0.484 \, \text{mol/L·s} \]
\[ \text{rate}_{NO_2} = 0.968 \, \text{mol/L·s} \]
Thus, the rate of formation of \( NO_2 \) is \( 0.968 \, \text{mol/L·s
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