4. A parking garage at UNM has installed an automatic gate. Unfortunately, the drivers have a probability of p of crashing into the gate, in which case it needs to be replaced. Also, if the gate has survived m days without a crash, it still must be replaced because of wear-and-tear. What is the long-term expected frequency of gate replacements Hint: Let the states of the Markov chain denote the number of days the gate has survived. Therefore, they should be a total of m+1 states. Finally, the long-term frequency of gate replacements is equal to the long-term expected frequency of visits to state 0.

A First Course in Probability (10th Edition)
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ISBN:9780134753119
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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4.
A parking garage at UNM has installed an automatic gate. Unfortunately, the drivers have a
probability of p of crashing into the gate, in which case it needs to be replaced. Also, if the gate has survived
m days without a crash, it still must be replaced because of wear-and-tear. What is the long-term expected
frequency of gate replacements
Hint: Let the states of the Markov chain denote the number of days the gate has survived. Therefore, ther
should be a total of m+1 states. Finally, the long-term frequency of gate replacements is equal to the long-term
expected frequency of visits to state 0.
Transcribed Image Text:4. A parking garage at UNM has installed an automatic gate. Unfortunately, the drivers have a probability of p of crashing into the gate, in which case it needs to be replaced. Also, if the gate has survived m days without a crash, it still must be replaced because of wear-and-tear. What is the long-term expected frequency of gate replacements Hint: Let the states of the Markov chain denote the number of days the gate has survived. Therefore, ther should be a total of m+1 states. Finally, the long-term frequency of gate replacements is equal to the long-term expected frequency of visits to state 0.
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