4. A parallel plate capacitor has a plate area of A = 2.0 m². The plates are separated by a gap of air with plate separation d = 3.0 mm. The permittivity of air is & = 8.85 × 10-¹² F/m. The breakdown electric field of air is 3.0 × 106 V/m. (a) Calculate the maximum quantity of charge that can be stored on the capacitor. (b) Calculate the maximum amount of electric energy that can be stored in the capacitor. (c) If the separation of the plates is increased with no other changes, would the answers to parts (a) and (b) above change? Explain with the help of formulas.
4. A parallel plate capacitor has a plate area of A = 2.0 m². The plates are separated by a gap of air with plate separation d = 3.0 mm. The permittivity of air is & = 8.85 × 10-¹² F/m. The breakdown electric field of air is 3.0 × 106 V/m. (a) Calculate the maximum quantity of charge that can be stored on the capacitor. (b) Calculate the maximum amount of electric energy that can be stored in the capacitor. (c) If the separation of the plates is increased with no other changes, would the answers to parts (a) and (b) above change? Explain with the help of formulas.
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Transcribed Image Text:4.
A parallel plate capacitor has a plate area of A = 2.0 m². The plates are separated by a
gap of air with plate separation d = 3.0 mm. The permittivity of air is & = 8.85 × 10-¹² F/m.
The breakdown electric field of air is 3.0 × 106 V/m.
(a) Calculate the maximum quantity of charge that can be stored on the capacitor.
(b) Calculate the maximum amount of electric energy that can be stored in the capacitor.
(c) If the separation of the plates is increased with no other changes, would the answers to
parts (a) and (b) above change? Explain with the help of formulas.
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