4. A drill is used to dig down into the earth. After 2 hours, the drill is 12 meters below the surface. After 5 hours, the drill is 30 meters below the surface. Which equation represents the depth of the drill in meters, y, after x hours of drilling? y = 12x b. у %3D-12х a. C. y = 6x d. y=-6x
4. A drill is used to dig down into the earth. After 2 hours, the drill is 12 meters below the surface. After 5 hours, the drill is 30 meters below the surface. Which equation represents the depth of the drill in meters, y, after x hours of drilling? y = 12x b. у %3D-12х a. C. y = 6x d. y=-6x
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![### Understanding Linear Equations: Practical Application
**Question 4:**
A drill is used to dig down into the earth. The depth to which the drill has reached is given at two different time intervals.
- After 2 hours, the drill is 12 meters below the surface.
- After 5 hours, the drill is 30 meters below the surface.
**Problem Statement:**
Which equation represents the depth of the drill in meters, \( y \), after \( x \) hours of drilling?
**Options:**
a. \( y = 12x \)
b. \( y = -12x \)
c. \( y = 6x \)
d. \( y = -6x \)
**Solution Explanation:**
To find the correct equation, consider the following:
1. **Determine the Depth Change:**
Compare the depth at different times; from 2 hours to 5 hours, the depth changes from 12 meters to 30 meters.
- Depth change = 30 meters - 12 meters = 18 meters.
2. **Determine the Time Change:**
- Time change = 5 hours - 2 hours = 3 hours.
3. **Calculate the Rate of Change (Slope):**
- Slope = Depth change / Time change = 18 meters / 3 hours = 6 meters per hour.
However, since the drill is moving downwards, this should be considered a negative slope, representing descent.
- Thus, slope = -6 meters/hour.
4. **Verify the Equation:**
- The equation with this slope consistent with the given changes in depth aligns with option d:
\[
y = -6x
\]
Therefore, the solution to the problem is **d. \( y = -6x \)**. This equation accurately represents the depth of the drill after \( x \) hours of drilling.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F604a8397-7cad-4f94-b592-137fb3c84f4a%2F5885ceb1-25a7-4d5c-b1ae-c64ad23b152b%2Fz53i08l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Linear Equations: Practical Application
**Question 4:**
A drill is used to dig down into the earth. The depth to which the drill has reached is given at two different time intervals.
- After 2 hours, the drill is 12 meters below the surface.
- After 5 hours, the drill is 30 meters below the surface.
**Problem Statement:**
Which equation represents the depth of the drill in meters, \( y \), after \( x \) hours of drilling?
**Options:**
a. \( y = 12x \)
b. \( y = -12x \)
c. \( y = 6x \)
d. \( y = -6x \)
**Solution Explanation:**
To find the correct equation, consider the following:
1. **Determine the Depth Change:**
Compare the depth at different times; from 2 hours to 5 hours, the depth changes from 12 meters to 30 meters.
- Depth change = 30 meters - 12 meters = 18 meters.
2. **Determine the Time Change:**
- Time change = 5 hours - 2 hours = 3 hours.
3. **Calculate the Rate of Change (Slope):**
- Slope = Depth change / Time change = 18 meters / 3 hours = 6 meters per hour.
However, since the drill is moving downwards, this should be considered a negative slope, representing descent.
- Thus, slope = -6 meters/hour.
4. **Verify the Equation:**
- The equation with this slope consistent with the given changes in depth aligns with option d:
\[
y = -6x
\]
Therefore, the solution to the problem is **d. \( y = -6x \)**. This equation accurately represents the depth of the drill after \( x \) hours of drilling.
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