What is the value of x when y = 9 in the equation y = 2x² + 1? O x = -5 Ox=0 Ox=2 Ox=2, -2 Ox= 3,5

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Question**: What is the value of \( x \) when \( y = 9 \) in the equation \( y = 2x^2 + 1 \)?

**Options**:

- \( x = -5 \)
- \( x = 0 \)
- \( x = 2 \)
- \( x = 2, -2 \)
- \( x = 3, 5 \)

**Explanation**:
To find \( x \), substitute \( y = 9 \) into the equation:

\( 9 = 2x^2 + 1 \)

Subtract 1 from both sides:

\( 8 = 2x^2 \)

Divide by 2:

\( 4 = x^2 \)

Take the square root of both sides:

\( x = 2 \) or \( x = -2 \)
Transcribed Image Text:**Question**: What is the value of \( x \) when \( y = 9 \) in the equation \( y = 2x^2 + 1 \)? **Options**: - \( x = -5 \) - \( x = 0 \) - \( x = 2 \) - \( x = 2, -2 \) - \( x = 3, 5 \) **Explanation**: To find \( x \), substitute \( y = 9 \) into the equation: \( 9 = 2x^2 + 1 \) Subtract 1 from both sides: \( 8 = 2x^2 \) Divide by 2: \( 4 = x^2 \) Take the square root of both sides: \( x = 2 \) or \( x = -2 \)
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