### Cross Section of a Typical Home Ceiling #### Given Data: - **Outside Temperature (\(T_{\text{outside}}\))**: \(-8^\circ C\) - **Inside Temperature (\(T_{\text{inside}}\))**: \(22^\circ C\) - **Heat Transfer Coefficients**: - \(h_o = 23 \, \text{W/m}^2 \cdot K\) - \(h_i = 8 \, \text{W/m}^2 \cdot K\) - **Material Thermal Conductivities**: - Fiberglass (\(k_{\text{fiberglass}}\)): \(0.036 \, \text{W/m} \cdot K\) - Wood (\(k_{\text{wood}}\)): \(0.17 \, \text{W/m} \cdot K\) - Plaster (\(k_{\text{plaster}}\)): \(0.824 \, \text{W/m} \cdot K\) #### Diagram Description: The diagram shows a cross section of a typical home ceiling. It illustrates a structure composed of: - **Pine Studs**: 6 cm wide - **Sections of Loose Fiberglass Insulation**: 30 cm wide - **Plaster**: Covering the underside, 2 cm thick #### Tasks: a) **Heat Transfer Calculation**: Use the given thermal properties to calculate the heat transfer through insulation and the studs. b) **R-38 Insulation Analysis**: Calculate the change in heat transfer if the insulation and studs are 12 inches thick as per R-38 insulation standards. This information aids in understanding and improving energy efficiency in building designs by evaluating material choices and insulation effectiveness.
### Cross Section of a Typical Home Ceiling #### Given Data: - **Outside Temperature (\(T_{\text{outside}}\))**: \(-8^\circ C\) - **Inside Temperature (\(T_{\text{inside}}\))**: \(22^\circ C\) - **Heat Transfer Coefficients**: - \(h_o = 23 \, \text{W/m}^2 \cdot K\) - \(h_i = 8 \, \text{W/m}^2 \cdot K\) - **Material Thermal Conductivities**: - Fiberglass (\(k_{\text{fiberglass}}\)): \(0.036 \, \text{W/m} \cdot K\) - Wood (\(k_{\text{wood}}\)): \(0.17 \, \text{W/m} \cdot K\) - Plaster (\(k_{\text{plaster}}\)): \(0.824 \, \text{W/m} \cdot K\) #### Diagram Description: The diagram shows a cross section of a typical home ceiling. It illustrates a structure composed of: - **Pine Studs**: 6 cm wide - **Sections of Loose Fiberglass Insulation**: 30 cm wide - **Plaster**: Covering the underside, 2 cm thick #### Tasks: a) **Heat Transfer Calculation**: Use the given thermal properties to calculate the heat transfer through insulation and the studs. b) **R-38 Insulation Analysis**: Calculate the change in heat transfer if the insulation and studs are 12 inches thick as per R-38 insulation standards. This information aids in understanding and improving energy efficiency in building designs by evaluating material choices and insulation effectiveness.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
only b
![### Cross Section of a Typical Home Ceiling
#### Given Data:
- **Outside Temperature (\(T_{\text{outside}}\))**: \(-8^\circ C\)
- **Inside Temperature (\(T_{\text{inside}}\))**: \(22^\circ C\)
- **Heat Transfer Coefficients**:
- \(h_o = 23 \, \text{W/m}^2 \cdot K\)
- \(h_i = 8 \, \text{W/m}^2 \cdot K\)
- **Material Thermal Conductivities**:
- Fiberglass (\(k_{\text{fiberglass}}\)): \(0.036 \, \text{W/m} \cdot K\)
- Wood (\(k_{\text{wood}}\)): \(0.17 \, \text{W/m} \cdot K\)
- Plaster (\(k_{\text{plaster}}\)): \(0.824 \, \text{W/m} \cdot K\)
#### Diagram Description:
The diagram shows a cross section of a typical home ceiling. It illustrates a structure composed of:
- **Pine Studs**: 6 cm wide
- **Sections of Loose Fiberglass Insulation**: 30 cm wide
- **Plaster**: Covering the underside, 2 cm thick
#### Tasks:
a) **Heat Transfer Calculation**: Use the given thermal properties to calculate the heat transfer through insulation and the studs.
b) **R-38 Insulation Analysis**: Calculate the change in heat transfer if the insulation and studs are 12 inches thick as per R-38 insulation standards.
This information aids in understanding and improving energy efficiency in building designs by evaluating material choices and insulation effectiveness.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F423822cb-5d3f-48f4-83a4-f0ba428ae79c%2F9bd907d9-50f8-43a4-aa8d-7ef8c4a9550e%2Fixowkuv_processed.png&w=3840&q=75)
Transcribed Image Text:### Cross Section of a Typical Home Ceiling
#### Given Data:
- **Outside Temperature (\(T_{\text{outside}}\))**: \(-8^\circ C\)
- **Inside Temperature (\(T_{\text{inside}}\))**: \(22^\circ C\)
- **Heat Transfer Coefficients**:
- \(h_o = 23 \, \text{W/m}^2 \cdot K\)
- \(h_i = 8 \, \text{W/m}^2 \cdot K\)
- **Material Thermal Conductivities**:
- Fiberglass (\(k_{\text{fiberglass}}\)): \(0.036 \, \text{W/m} \cdot K\)
- Wood (\(k_{\text{wood}}\)): \(0.17 \, \text{W/m} \cdot K\)
- Plaster (\(k_{\text{plaster}}\)): \(0.824 \, \text{W/m} \cdot K\)
#### Diagram Description:
The diagram shows a cross section of a typical home ceiling. It illustrates a structure composed of:
- **Pine Studs**: 6 cm wide
- **Sections of Loose Fiberglass Insulation**: 30 cm wide
- **Plaster**: Covering the underside, 2 cm thick
#### Tasks:
a) **Heat Transfer Calculation**: Use the given thermal properties to calculate the heat transfer through insulation and the studs.
b) **R-38 Insulation Analysis**: Calculate the change in heat transfer if the insulation and studs are 12 inches thick as per R-38 insulation standards.
This information aids in understanding and improving energy efficiency in building designs by evaluating material choices and insulation effectiveness.
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