4. A chandelier is supported up by two ropes. a) Find the tension in the ropes. b) The rope on the left,T₁, is cut. What is the magnitude of the acceleration of the chandelier immediately after the rope is cut? T1 40° 20° Τη mg = 500N 4. chandelier: a) T₁ = 543N T2 = 442 N b) Before it was cut Ţ₁ + T₂ + mg = 0 just after the rope is cut, ΣF = T₂+ mg = -T₁ |ΣF❘ = 10.6 m/s² m (the direction is to the right and downward, opposite of the direction of T₁) T₁
4. A chandelier is supported up by two ropes. a) Find the tension in the ropes. b) The rope on the left,T₁, is cut. What is the magnitude of the acceleration of the chandelier immediately after the rope is cut? T1 40° 20° Τη mg = 500N 4. chandelier: a) T₁ = 543N T2 = 442 N b) Before it was cut Ţ₁ + T₂ + mg = 0 just after the rope is cut, ΣF = T₂+ mg = -T₁ |ΣF❘ = 10.6 m/s² m (the direction is to the right and downward, opposite of the direction of T₁) T₁
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter6: Applications Of Newton’s Laws Of Motion
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Problem 11PQ: In Problem 10, the mass of the sign is 25.4 kg, and the mass of the potted plant is 66.7 kg. a....
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can someone help me with explaining part B?

Transcribed Image Text:4. A chandelier is supported up by two ropes.
a) Find the tension in the ropes.
b) The rope on the left,T₁, is cut. What is the magnitude of the
acceleration of the chandelier immediately after the rope is cut?
T1
40°
20°
Τη
mg = 500N

Transcribed Image Text:4. chandelier: a) T₁ = 543N T2 = 442 N
b) Before it was cut Ţ₁ + T₂ + mg = 0
just after the rope is cut, ΣF = T₂+ mg = -T₁
|ΣF❘
= 10.6 m/s²
m
(the direction is to the right and downward, opposite of the direction of T₁)
T₁
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