4. A body moves a distance of 10 m under the action of a force that has a constant value of 5.5 N for the first 6 m. How much work is done in the first 6 m of the motion?
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Q: 4. A runner has 250 J of KE. A short time later, he has 150 J of KE. How much Work was done on him?
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A: Given data: Initial velocity (v0) = 0 m/s Work done (W) = 550 J Required: Final kinetic Energy
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A: He pushes the car a distance of s=20 m. Frictional Force =35 N .
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A: See below
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Q: the work done by the force
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A: FORCE=100n DISPLACEMENT=5M work done by you=(force)(displacement)=100 X 5m=500J (ANSWER)
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