4) You design Drosophila crosses to provide recombination data for gene (A), which is located somewhere on the chromosome shown below: Short aristae Long aristae (appendages on head) Black body Gray body Mutant phenotypes Cinnabar eyes 48.5 57.5 Red eyes 67.0 Vestigial wings Normal wings Brown eyes 104.5 Red eyes Wild-type phenotypes Gene (A) has a recombination frequency of 14% with the vestigial-wing locus and 23% with the brown- eye locus. Where is gene (A) located on this chromosome?
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- Drosophila researchers have collected many strainsthat carry a single recombinant P element containing awild-type white gene (a P[w+] transgene) inserted intoa known genomic location. These strains can be used tomap the location of any mutant gene in the fly genome.Investigators performed a testcross to map arecessive mutation rough (ro), which causes rougheyes, relative to a P[w+] element on chromosome 3.Females heterozygous for the P[w+] on one chromosome 3 and a ro− mutation on the other, homologouschromosome 3 were crossed to ro−/ro− males, and theprogeny in the following list were obtained. In boththe parents and the progeny, the endogenous whitegene is nonfunctional—the flies have red eyes onlyif they contain the P[w+] transgene.145 red, smooth (wild-type) eyes152 white, rough eyes2 white, smooth eyes1 red, rough eyesa. Are ro and the P[w+] linked? If so, how many mapunits separate them?b. The data in part (a) do not indicate on which sideof the P[w+] (toward the centromere or…The Drosophila chromosome 4 is extremely small;virtually no recombination occurs between genes onthis chromosome. You have available three differentlymarked chromosome 4s: one has a recessive allele ofthe gene eyeless (ey), causing very small eyes; one hasa recessive allele of the cubitus interruptus (ci) gene,which causes disruptions in the veins on the wings;and the third carries recessive alleles of both genes.Drosophila adults can survive with two or three, butnot with one or four, copies of chromosome 4.a. How could you use these three chromosomes tofind Drosophila mutants with defective meiosescausing an elevated rate of nondisjunction?b. Would your technique allow you to discriminatenondisjunction occurring during the first meioticdivision from nondisjunction occurring during thesecond meiotic division?c. What progeny types would you expect if a flyrecognizably formed from a gamete produced bynondisjunction were testcrossed to a fly homozygous for a chromosome 4 carrying both ey…The Drosophila chromosome 4 is extremely small;virtually no recombination occurs between genes onthis chromosome. You have available three differentlymarked chromosome 4s: one has a recessive allele ofthe gene eyeless (ey), causing very small eyes; one hasa recessive allele of the cubitus interruptus (ci) gene,which causes disruptions in the veins on the wings;and the third carries recessive alleles of both genes.Drosophila adults can survive with two or three, butnot with one or four, copies of chromosome 4.a. How could you use these three chromosomes tofind Drosophila mutants with defective meiosescausing an elevated rate of nondisjunction?b. Would your technique allow you to discriminatenondisjunction occurring during the first meioticdivision from nondisjunction occurring during thesecond meiotic division?
- A Drosophila embryo dies during early embryogenesis due to arecessive maternal effect allele called bicoid−. The wild-type alleleis designated bicoid+. What are the genotypes and phenotypes ofthe embryo’s mother and maternal grandparents?A Drosophila male is heterozygous for a reciprocaltranslocation between an autosome and the Y chromosome. The part of the autosome now present onthe Y chromosome contains the dominant mutationLyra (shortened wings); the other (normal) copyof the same autosome is Lyra+. This male is nowmated with a true-breeding, wild-type female. Whatkinds of progeny would be obtained, and in whatproportions?Drosophila P elements were discovered because ofa phenomenon called hybrid dysgenesis—sterilityof particular hybrid progeny. When scientists in the1970s crossed their D. melanogaster laboratorystrains to flies of the same species obtained fromnatural environments outside the lab, they observeda remarkable result: The progeny of the crosseswere sterile, but only when outside males werecrossed with lab strain females. Progeny resultingfrom crosses of outside females with lab maleswere perfectly normal.DNA analysis revealed that while the genomesof the outside flies contain P elements, the lab flygenomes have none. Apparently, P elements spreadthroughout the wild population of D. melanogasterafter the capture of the originators of present-daylaboratory strains over 100 years ago.a. The hybrid progeny are sterile because their germline cells have a high rate of mutation and chromosomal rearrangement (dysgenesis) caused by highrates of P element mobilization. Explain howP element movement…
- Classes SBI3C1-2 rr x rr Meet - rz pQLSeUir31BTTSeUl8EYpVNYpajrmzBg_g0n6oMivineMfM4k0w/viewform rr x Rr Classwork O Rrx Rr ORR X Rr Genet X SBI3C1-2 Genetics Two parents were known to be right-handed. Assuming that right-handed (R) is dominant to left-handed (r), what would be the genotypes of the parents if their son is left-handed? Google M Post Atte Sp * 1 poirISlate edu/ d2l/le/content/5003190/viewContent/44248878/View Google Tranx 4 My Drive-G X 4. Suppose that a parent Drosophila is e ca* ca The gamete frequency is as follows: e'ca e ca 16% e'ca е са 31% 14% 29% a. Circle the recombinant gametes. b. What is the map distance between the ebony and claret genes?In Drosophila, a cross (cross 1) was made between twomutant flies, one homozygous for the recessive mutationbent wing (b) and the other homozygous for the recessivemutation eyeless (e). The mutations e and b are alleles oftwo different genes that are known to be very closelylinked on the tiny autosomal chromosome 4. All the progeny had a wild-type phenotype. One of the female progeny was crossed with a male of genotype b e/b e ; we willcall this cross 2. Most of the progeny of cross 2 were of theexpected types, but there was also one rare female ofwild-type phenotype.a. Explain what the common progeny are expected tobe from cross 2.b. Could the rare wild-type female have arisen by (1)crossing over or (2) nondisjunction? Explain.
- Drosophila females heterozygous for each of three recessive autosomal mutations with independent phenotypic effects [thread antennae (th), hairy body (h), andscarlet eyes (st)] were testcrossed to males showingall three mutant phenotypes. The 1000 progeny of thistestcross werethread, hairy, scarlet 432wild type 429thread, hairy 37thread, scarlet 35hairy 34scarlet 33a. Show the arrangement of alleles on the relevantchromosomes in the triply heterozygous females.b. Draw the best genetic map that explains these data.c. Calculate any relevant interference valuesThe following list of four Drosophila mutations indicates the symbol for the mutation, the name of thegene, and the mutant phenotype:Allele symbol Gene name Mutant phenotypedwp dwarp small body, warped wingsrmp rumpled deranged bristlespld pallid pale wingsrv raven dark eyes and bodiesYou perform the following crosses with the indicatedresults:Cross #1: dwarp, rumpled females × pallid, raven males→ dwarp, rumpled males and wild-type femalesCross #2: pallid, raven females × dwarp, rumpled males→ pallid, raven males and wild-type femalesF1 females from cross #1 were crossed to males froma true-breeding dwarp rumpled pallid raven stock.The 1000 progeny obtained were as follows:pallid 3pallid, raven 428pallid, raven, rumpled 48pallid, rumpled 23dwarp, raven 22dwarp, raven, rumpled 2dwarp, rumpled 427dwarp 47Indicate the best map for these four genes, includingall relevant data. Calculate interference values whereappropriate.6. A diploid strain of yeast was made by mating a haploidstrain with a genotype w−, x−, y−, and z− with a haploidstrain of opposite mating type that is wild type for thesefour genes. The diploid strain was phenotypically wildtype. Four different X-ray-induced diploid mutantswith the following phenotypes were produced fromthis diploid yeast strain. Assume a single new mutation is present in each strain.Strain 1 w− x+ y− z+Strain 2 w+ x− y− z−Strain 3 w− x+ y− z−Strain 4 w− x+ y+ z+When these mutant diploid strains of yeast go throughmeiosis, each ascus is found to contain only two viablehaploid spores.a. What kind of mutations were induced by X-rays tomake the listed diploid strains?b. Why did two spores in each ascus die?