4) Use your free body diagram and the idea of centripetal acceleration to identify the mistake in each student's statement: Student 1: "The Moon is in space. Therefore, there cannot be any forces on the moon. That is why the moon stays up in the sky instead of crashing into the Earth." Student 2: "There should be two forces on the Moon: a gravity force toward the Earth and a centrifugal force pointing away from the Earth. Because these two forces are balanced the Moon does not crash into the Earth. Student 3: "There should only be one force on the Moon- the force of gravity toward the Earth. However, because the Moon is so far away, the force of gravity is too weak to move that much mass, that is why the Moon does not crash into the Earth."
4) Use your free body diagram and the idea of centripetal acceleration to identify the mistake in each student's statement: Student 1: "The Moon is in space. Therefore, there cannot be any forces on the moon. That is why the moon stays up in the sky instead of crashing into the Earth." Student 2: "There should be two forces on the Moon: a gravity force toward the Earth and a centrifugal force pointing away from the Earth. Because these two forces are balanced the Moon does not crash into the Earth. Student 3: "There should only be one force on the Moon- the force of gravity toward the Earth. However, because the Moon is so far away, the force of gravity is too weak to move that much mass, that is why the Moon does not crash into the Earth."
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
![Sure! Here is the transcription of the provided image:
---
Feel free to use the following data to complete your calculations:
\[
G = 6.67 \times 10^{-11} \frac{Nm^2}{kg^2}
\]
\[
M_{Sun} = 1.989 \times 10^{30} \, kg
\]
**Moon:**
- \( T_{moon\ around\ Earth} = 27.3 \, days \)
- \( M_{moon} = 7.34 \times 10^{22} \, kg \)
- \( r_{Moon\ to\ Earth} = 3.84 \times 10^{8} \, m \)
- \( r_{Moon\ center\ to\ Moon\ surface} = 1.74 \times 10^{6} \, m \)
**Earth:**
- \( T_{Earth\ around\ Sun} = 365.25 \, days \)
- \( M_{Earth} = 5.97 \times 10^{24} \, kg \)
- \( r_{Earth\ to\ Moon} = 3.84 \times 10^{8} \, m \)
- \( r_{Earth\ center\ to\ Earth\ surface} = 6.37 \times 10^{6} \, m \)
---
The image does not contain any graphs or diagrams.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F21ec5513-8136-491c-9bc9-2f1a8372f6ef%2F8c306a3a-9e71-48ca-8ef5-8c7f30eaca91%2Fyex3di7_processed.png&w=3840&q=75)
Transcribed Image Text:Sure! Here is the transcription of the provided image:
---
Feel free to use the following data to complete your calculations:
\[
G = 6.67 \times 10^{-11} \frac{Nm^2}{kg^2}
\]
\[
M_{Sun} = 1.989 \times 10^{30} \, kg
\]
**Moon:**
- \( T_{moon\ around\ Earth} = 27.3 \, days \)
- \( M_{moon} = 7.34 \times 10^{22} \, kg \)
- \( r_{Moon\ to\ Earth} = 3.84 \times 10^{8} \, m \)
- \( r_{Moon\ center\ to\ Moon\ surface} = 1.74 \times 10^{6} \, m \)
**Earth:**
- \( T_{Earth\ around\ Sun} = 365.25 \, days \)
- \( M_{Earth} = 5.97 \times 10^{24} \, kg \)
- \( r_{Earth\ to\ Moon} = 3.84 \times 10^{8} \, m \)
- \( r_{Earth\ center\ to\ Earth\ surface} = 6.37 \times 10^{6} \, m \)
---
The image does not contain any graphs or diagrams.

Transcribed Image Text:**Question:**
Use your free body diagram and the idea of centripetal acceleration to identify the mistake in each student’s statement:
**Student 1:**
“The Moon is in space. Therefore, there cannot be any forces on the moon. That is why the moon stays up in the sky instead of crashing into the Earth.”
**Student 2:**
“There should be two forces on the Moon: a gravity force toward the Earth and a centrifugal force pointing away from the Earth. Because these two forces are balanced, the Moon does not crash into the Earth.”
**Student 3:**
“There should only be one force on the Moon—the force of gravity toward the Earth. However, because the Moon is so far away, the force of gravity is too weak to move that much mass, that is why the Moon does not crash into the Earth.”
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you

College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning

University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press

College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning

University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press

Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning

Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley

College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON