4) The position of a particle is given by x = 4.50 e-030r, where x has units of meters. What is (a) the average velocity between 2.00 and 3.00 s; (b) the instantaneous velocity at 2.00 s; (c) the instantaneous acceleration at 2.00 s.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Number 4 can you solve for some using formula ?
Homework #2
1) Based on the graph below estimate the instantaneous velocity at the following times: (a)
1.0 s; (b) 2.5 s; (c) 3.5 s; (d) 4.5 s; (e) 5.0 s;
(m)
15E
10E
t (s)
1
4
2) At t= 2.25 s a particle is at x=7.00 m and has velocity v = 3.50 m/s. At t = 7.00 s, it is at
x = -5.10 m and has velocity v= 6.00 m/s. Find: (a) its average velocity; (b) its average
acceleration.
3) The figure below shows the v versus t graphs for cars A and B. At t= 0 both are at x = 0.
Estimate: (a) where and when they meet again; and (b) their velocities when they meet.
(m/s)
12
8
4
t (s)
4) The position of a particle is given by x = 4.50 e¬0.30t, where x has units of meters. What
is (a) the average velocity between 2.00 and 3.00 s; (b) the instantaneous velocity at 2.00 s;
(c) the instantaneous acceleration at 2.00 s.
5) A Honda Fit is initially with a speed of 115 km/h. Find its acceleration and the time taken
to stop given that: (a) it brakes to a stop in 64.0 m; (b) it crashes head-on into a barrier and
crumples by 1.00 m.
6) An object moves with constant acceleration. Att= 2.50 s, the position of the object is
x= 2.00 m and its velocity is v= 4.50 m/s. At t = 7.00 s, v= -12.0 m/s. Find: (a) the
position and the velocity at t = 0; (b) the average speed from 2.50 s to 7.00 s, and (c) the
average velocity from 2.50 s to 7.00 s.
7) A ball thrown vertically up from the ground rises to height of 24.0 m. How high would it rise
on the moon if given the same initial speed? The acceleration due to gravity on the moon is one-
sixth that on earth.
8) A ball is thrown up from the top of a building 55.0 m high. It rises to a maximum height
of 20.0 m above the roof. (a) When does it land on the ground below? (b) At what velocity
does it land? (c) When is it 20.0 m below the roof?
Transcribed Image Text:Homework #2 1) Based on the graph below estimate the instantaneous velocity at the following times: (a) 1.0 s; (b) 2.5 s; (c) 3.5 s; (d) 4.5 s; (e) 5.0 s; (m) 15E 10E t (s) 1 4 2) At t= 2.25 s a particle is at x=7.00 m and has velocity v = 3.50 m/s. At t = 7.00 s, it is at x = -5.10 m and has velocity v= 6.00 m/s. Find: (a) its average velocity; (b) its average acceleration. 3) The figure below shows the v versus t graphs for cars A and B. At t= 0 both are at x = 0. Estimate: (a) where and when they meet again; and (b) their velocities when they meet. (m/s) 12 8 4 t (s) 4) The position of a particle is given by x = 4.50 e¬0.30t, where x has units of meters. What is (a) the average velocity between 2.00 and 3.00 s; (b) the instantaneous velocity at 2.00 s; (c) the instantaneous acceleration at 2.00 s. 5) A Honda Fit is initially with a speed of 115 km/h. Find its acceleration and the time taken to stop given that: (a) it brakes to a stop in 64.0 m; (b) it crashes head-on into a barrier and crumples by 1.00 m. 6) An object moves with constant acceleration. Att= 2.50 s, the position of the object is x= 2.00 m and its velocity is v= 4.50 m/s. At t = 7.00 s, v= -12.0 m/s. Find: (a) the position and the velocity at t = 0; (b) the average speed from 2.50 s to 7.00 s, and (c) the average velocity from 2.50 s to 7.00 s. 7) A ball thrown vertically up from the ground rises to height of 24.0 m. How high would it rise on the moon if given the same initial speed? The acceleration due to gravity on the moon is one- sixth that on earth. 8) A ball is thrown up from the top of a building 55.0 m high. It rises to a maximum height of 20.0 m above the roof. (a) When does it land on the ground below? (b) At what velocity does it land? (c) When is it 20.0 m below the roof?
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