4) The impurity of zinc in liquid lead can be removed by passing chlorine gas at 390 °C according to the following reaction: Zn(liquid alloy) + PbCl;(slag) 2 Pb(liquid alloy) + ZnCl,(slag) AG° = -63137 J is given for the above reaction at 390 °C. The composition of the final slag is xzncl, = 0.983 . For the very dilute solution of Zn in the above liquid alloy, its activity is given as azn = 29xzn - Assuming the ideal behavior for the slag phase and the nearly pure Pb, calculate the level to which the removal of zinc (in mole fraction) can be carried out. Hint: Xpp + Xzn = 1 for the liquid alloy and xzncl, + Xpbcl, = 1 for the slag phase.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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4) The impurity of zinc in liquid lead can be removed by passing chlorine gas at 390 °C according to the
following reaction:
Zn(liquid alloy) + PbCl_(slag) 2 Pb(liquid alloy) + ZnCl,(slag)
AG° = -63137 J is given for the above reaction at 390 °C. The composition of the final slag is xzncl, =
0.983. For the very dilute solution of Zn in the above liquid alloy, its activity is given as azn = 29xzn -
%3D
Assuming the ideal behavior for the slag phase and the nearly pure Pb, calculate the level to which the
removal of zinc (in mole fraction) can be carried out.
Hint: Xpp + Xzn = 1 for the liquid alloy and xzncl, + Xpbcl, = 1 for the slag phase.
AG = AG° + RTINQ
AG° = -RTINK
ai = X;Yi
AGideal = RT(Xalnx4 + Xglnxg)
AG*S = XAuXNi
> "LAu.Ni(Xau – XNi)"
R = 8.314 J. mol-1.K-1 = 1.987cal.mol-1.K-1
Transcribed Image Text:4) The impurity of zinc in liquid lead can be removed by passing chlorine gas at 390 °C according to the following reaction: Zn(liquid alloy) + PbCl_(slag) 2 Pb(liquid alloy) + ZnCl,(slag) AG° = -63137 J is given for the above reaction at 390 °C. The composition of the final slag is xzncl, = 0.983. For the very dilute solution of Zn in the above liquid alloy, its activity is given as azn = 29xzn - %3D Assuming the ideal behavior for the slag phase and the nearly pure Pb, calculate the level to which the removal of zinc (in mole fraction) can be carried out. Hint: Xpp + Xzn = 1 for the liquid alloy and xzncl, + Xpbcl, = 1 for the slag phase. AG = AG° + RTINQ AG° = -RTINK ai = X;Yi AGideal = RT(Xalnx4 + Xglnxg) AG*S = XAuXNi > "LAu.Ni(Xau – XNi)" R = 8.314 J. mol-1.K-1 = 1.987cal.mol-1.K-1
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