* = (4) + * Please explan steps (in defail) A positively charged particle is held at the center of a spherical shell. The figure gives the magnitude E of the electric feld versus radial distancer. The scale of the vertical axis is set by E, = 14.5 10 N/C. Approximately, what is the net charge on the shell? Assume r, ,-3 cm, Step 1 Given The scale of the vertical axis E, = 14.5 x 10" N/C = 3 cm () 21, r(Cm) Find the net charge on the shell as following below. Step 2 The electric field inside a conductor is zero. Hence, the electric field at r= 2.5 rs, is due to the particle only. The electric field due to the charged particle at the center is as follows : Ej = * why is E not equal to Es ? Please explain hous from A to Bi (2.5 r,) * From the graph, E1 = 10 ka 25 r you got ..... (1) Let Q be the charge on the shell. The electric field at r = 3 r, is due to both shell and the particle. E3 = ko + (: B = 4) 97 e Then, using equation (1) 119 E, 180 Using Equation () 119 r; E, Thenk you!! 20 k and fernl conect anawer using ts =3Cm 4 (01 א/(:

* = (4) + * Please explan steps (in defail) A positively charged particle is held at the center of a spherical shell. The figure gives the magnitude E of the electric feld versus radial distancer. The scale of the vertical axis is set by E, = 14.5 10 N/C. Approximately, what is the net charge on the shell? Assume r, ,-3 cm, Step 1 Given The scale of the vertical axis E, = 14.5 x 10" N/C = 3 cm () 21, r(Cm) Find the net charge on the shell as following below. Step 2 The electric field inside a conductor is zero. Hence, the electric field at r= 2.5 rs, is due to the particle only. The electric field due to the charged particle at the center is as follows : Ej = * why is E not equal to Es ? Please explain hous from A to Bi (2.5 r,) * From the graph, E1 = 10 ka 25 r you got ..... (1) Let Q be the charge on the shell. The electric field at r = 3 r, is due to both shell and the particle. E3 = ko + (: B = 4) 97 e Then, using equation (1) 119 E, 180 Using Equation () 119 r; E, Thenk you!! 20 k and fernl conect anawer using ts =3Cm 4 (01 א/(:

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

* = (4) + * Please explan steps (in defail)
A positively charged particle is held at the center of a spherical shell. The figure gives the magnitude E of the electric fcld versus radial
distancer. The scale of the vertical axis is set by E, = 14.5 x 10 N/C. Approximately, what is the net charge on the shell?
Assumer, - 3 cm.
Step 1
Given
The scale of the vertical axis E, = 14. 5 x 10" N/C
=3 cm
()
2,
r(Cm)
Find the net charge on the shell as following below.
Step 2
The clectric field inside a conductor is zero.
Hence, the electric field at r= 2.5 rs, is due to the particle only.
The electric field due to the charged particle at the center is as
follows :
Ej =
(2.5r,
Is Ei not equal to Es ?
10
* From the graph, E¡ =
A
B = 5
* why is
Please explain hous you got
from A to B.
.....(1)
Let Q be the charge on the shell.
The electric field at r = 3 r, is due to. both shell and the particle.
E3 =
(3 r,
(3r,
(: E = 4)
%3D
%3D
* Then, using equation (1)
119 E,
180
%3D
Using Equation )
119 r; E,
Thank you !!
20 k
and fernl corcct
Anawer using ts =3cm

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