Solve the following problems. Show your solution. (Use the BLUE Curve)4 Ip (mA)2어19Actual commerciallyavailable unit18-1716Eq. (1)1514+1312-11-10-Defined polarity anddirection for graphVp+-9+8-7-Forward-bias regionVp >0 V, Ip>0 mA).-6-5+4+3--2-1--30 -20-10Vo (V)0.310 pA20 pA30 pA-40 pA50 pA-40050.7Reverse-bias region(Vp <0 V, Ip =-1,)No-bias(Vo -0V, Ip=0 mA)FIG. 15Silicon semiconductor diode characteristics. 27. Determine the static or de resistance of the commercially available diode of Fig. 15 at a for-ward current of 4 mA.28. Repeat Problem 27 at a forward current of 15 mA and compare results.29. Determine the static or de resistance of the commercially available diode of Fig. 15 at a reversevoltage of – 10 V. How does it compare to the value determined at a reverse voltage of – 30 V?

Answered: Image /qna-images/answer/6194ab8e-5eef-4ecc-b21a-58cd46d7c024.jpg

4 Ip (mA) 20 19 Actual commercially available unit 18 17 16 15 14 Eq. (1) 13 12 Defined polarity and direction for graph 10 9- 8- 7+ 6+ Forward-bias region Vp >0 V, Ip>0 mA)- 40 -30 -20 -10 03 10 pA 20 pA (V-OV, Ip 0 mA) -30 pA 0.5 0,7 Vo(V) Reverse-bias region (Vp <0 V, Ip=-1,) No-bias. 40 pA -50 pA FIG. 15 Silicon semiconductor diode characteristics.

4 Ip (mA) 20 19 Actual commercially available unit 18 17 16 15 14 Eq. (1) 13 12 Defined polarity and direction for graph 10 9- 8- 7+ 6+ Forward-bias region Vp >0 V, Ip>0 mA)- 40 -30 -20 -10 03 10 pA 20 pA (V-OV, Ip 0 mA) -30 pA 0.5 0,7 Vo(V) Reverse-bias region (Vp <0 V, Ip=-1,) No-bias. 40 pA -50 pA FIG. 15 Silicon semiconductor diode characteristics.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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