4 If you could assume this data is normally distributed, what would the critical value be if the professor wanted to assess of the students average was different than 90. Let -0.05. 1.960 1.729 2.093 1.645 34 If you could assume this data is normally distributed, what would the value of the test statistic be? Round to 2 decimal places. Type your answer.... $ 35 If you could assume this data is normally distributed, what would your conclusion be if the professor wanted to determine if the students' average was higher than 80? Let a 0.05. There is not enough evidence to conclude that the students' average is above 80. There is enough evidence to conclude that the students' average is above 80. Fail to reject Ho. Reject Ho.

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4
If you could assume this data is normally distributed, what would the critical value be if the professor wanted to assess if the students average was different than 80. Let
-0.05.
1.960
1.729
2.093
1.645
34
If you could assume this data is normally distributed, what would the value of the test statistic be? Round to 2 decimal places.
Type your answer...
35
If you could assume this data is normally distributed, what would your conclusion be if the professor wanted to determine if the students' average was higher than 80?
Let a 0.05.
There is not enough evidence to conclude that the students' average is above 80.
There is enough evidence to conclude that the students' average is above 80.
Fail to reject Ho.
Reject Ho.
Transcribed Image Text:4 If you could assume this data is normally distributed, what would the critical value be if the professor wanted to assess if the students average was different than 80. Let -0.05. 1.960 1.729 2.093 1.645 34 If you could assume this data is normally distributed, what would the value of the test statistic be? Round to 2 decimal places. Type your answer... 35 If you could assume this data is normally distributed, what would your conclusion be if the professor wanted to determine if the students' average was higher than 80? Let a 0.05. There is not enough evidence to conclude that the students' average is above 80. There is enough evidence to conclude that the students' average is above 80. Fail to reject Ho. Reject Ho.
Use the following JMP output:
Students' Exam 1 scores were collected from STA 2381 and are represented by the following:
4- Exam 1
30 40 50 60 70 80 90
100
Quantiles
100.0% maximum
99.5%
97.5%
90.0%
75.0%
50.0%
25.0%
10.0%
2.5%
0.5%
0.0%
quartile
median
minimum
97
97
97
92.7
85.25
71.5
61
42.1
32
32
32
- Summary Statistics
Mean
Std Dev
Std En Mean
Upper 95% Mean
Lower 95% Mean
N
70.7
16.730369
37410243
78.530054
62.869946
20
Test Mean
Hypothesired Value
Actual Estimate
DE
Std Dev
Test Statistik
Prob > M
Prob
Prob
BO
70.7
19
16.7304
1 Test
-24860
60224
0.9868
0.0112
70 75 80 65 90
Confidence Intervals
Parameter Estimate Lower C Upper C 1 Alpha
Mean
Sid Dev
70.7 59.99117 1.40283
1673037 11.74055 27.47586
0,990
0.500
Transcribed Image Text:Use the following JMP output: Students' Exam 1 scores were collected from STA 2381 and are represented by the following: 4- Exam 1 30 40 50 60 70 80 90 100 Quantiles 100.0% maximum 99.5% 97.5% 90.0% 75.0% 50.0% 25.0% 10.0% 2.5% 0.5% 0.0% quartile median minimum 97 97 97 92.7 85.25 71.5 61 42.1 32 32 32 - Summary Statistics Mean Std Dev Std En Mean Upper 95% Mean Lower 95% Mean N 70.7 16.730369 37410243 78.530054 62.869946 20 Test Mean Hypothesired Value Actual Estimate DE Std Dev Test Statistik Prob > M Prob Prob BO 70.7 19 16.7304 1 Test -24860 60224 0.9868 0.0112 70 75 80 65 90 Confidence Intervals Parameter Estimate Lower C Upper C 1 Alpha Mean Sid Dev 70.7 59.99117 1.40283 1673037 11.74055 27.47586 0,990 0.500
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