4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSO4 with a offer amount of Zn equal to 6 x 10 mol, the percentage yield of (Cu) according to the equation: CuSO(ag)+Zn(s) ZnSO. (aq) +Cu (s) a) 75% b) 83% c) 65% d) 90%.
4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSO4 with a offer amount of Zn equal to 6 x 10 mol, the percentage yield of (Cu) according to the equation: CuSO(ag)+Zn(s) ZnSO. (aq) +Cu (s) a) 75% b) 83% c) 65% d) 90%.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSO
with a offer amount of Zn equal to 6 x 103 mol, the percentage yield of (Cu)
according to the equation :
CuSO.(ag)+Zn(s) ZnSO. (ag) +Cu (s)
a) 75%
b) 83%
c) 65%
d) 90%.
5) For the following reaction:
I (g) + H: (g) → 2HI (g)
If the amount consumed from (I) according to the above reaction is (50.8g) and the
actual yield of HI is (40g) then the percentage yield of (HI) is equal to :
a) 78.125%
b) 15.625%
c) 63.341%
d)39.06% .
6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH according
to the equation:
HNO. + LIOH → LINO, + HO
a) 46
) 29
c) 2
d) 11
31
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4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSO
with a offer amount of Zn equal to 6 x 103 mol, the percentage yield of (Cu)
according to the equation :
CuSO.(ag)+Zn(s) ZnSO. (ag) +Cu (s)
a) 75%
b) 83%
c) 65%
d) 90%.
5) For the following reaction:
I (g) + H: (g) → 2HI (g)
If the amount consumed from (I) according to the above reaction is (50.8g) and the
actual yield of HI is (40g) then the percentage yield of (HI) is equal to :
a) 78.125%
b) 15.625%
c) 63.341%
d)39.06% .
6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH according
to the equation:
HNO. + LIOH → LINO, + HO
a) 46
) 29
c) 2
d) 11
31
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a) 78.125%
d)39 06% -
b) 15.625%
c) 63.341%
6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH according
to the equation:
HNO, +LIOH → LINO, + H. O
a) 46
b) 29
c) 2
d) 11
7) The mass of potassium hydroxide (KOH) to be dissolved in (100 ml) of water to
obtain a solution of 0.25M concentration is:
a) 1.4g
b) 4.5g
c) 0.025g
d) 5.6g .
8) Molarity (5g) of NaOH dissolved in 120 ml of solution the molar is :
a) 0.75M
b) 1. 04M
c) 1.25M
d) 0.5M
9) How many grams of A1C1 should be dissolved, to prepare 1 liter of a solution
in which the concentration of Cl ions 0.6M?
a) 240.3 grams
b) 80.1 grams
c) 26.7 grams
d) 41.1 grams
10) For the following reaction:
2A + 3B - 2AB
Atomic a Weights A= 27 &B= 35.5
The number of grams of AB. consisting of (12g) interaction of B:
a) 26.2g
Molecular weight AB = 133.5 g mol
b) 15.04g
c) 20g
d) 31.4g
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a) 78.125%
d)39 06% -
b) 15.625%
c) 63.341%
6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH according
to the equation:
HNO, +LIOH → LINO, + H. O
a) 46
b) 29
c) 2
d) 11
7) The mass of potassium hydroxide (KOH) to be dissolved in (100 ml) of water to
obtain a solution of 0.25M concentration is:
a) 1.4g
b) 4.5g
c) 0.025g
d) 5.6g .
8) Molarity (5g) of NaOH dissolved in 120 ml of solution the molar is :
a) 0.75M
b) 1. 04M
c) 1.25M
d) 0.5M
9) How many grams of A1C1 should be dissolved, to prepare 1 liter of a solution
in which the concentration of Cl ions 0.6M?
a) 240.3 grams
b) 80.1 grams
c) 26.7 grams
d) 41.1 grams
10) For the following reaction:
2A + 3B - 2AB
Atomic a Weights A= 27 &B= 35.5
The number of grams of AB. consisting of (12g) interaction of B:
a) 26.2g
Molecular weight AB = 133.5 g mol
b) 15.04g
c) 20g
d) 31.4g
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