homework5 (Compatibility Mode]- Word (Product Activation Failed)cesMailingsReviewViewTell me what you want to do.AaBbCcD AaBbCcDc AaBbC AaBbCcl Aa. AI NormalT No Spac.. Heading 1 Heading 2TitleParagraphStyles4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSOwith a offer amount of Zn equal to 6 x 103 mol, the percentage yield of (Cu)according to the equation :CuSO.(ag)+Zn(s) ZnSO. (ag) +Cu (s)a) 75%b) 83%c) 65%d) 90%.5) For the following reaction:I (g) + H: (g) → 2HI (g)If the amount consumed from (I) according to the above reaction is (50.8g) and theactual yield of HI is (40g) then the percentage yield of (HI) is equal to :a) 78.125%b) 15.625%c) 63.341%d)39.06% .6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH accordingto the equation:HNO. + LIOH → LINO, + HOa) 46) 29c) 2d) 1131hp AaBbCcDc AaBbCcDr AaBbC前,I No Spac. Heading 1TNormalParagrapha) 78.125%d)39 06% -b) 15.625%c) 63.341%6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH accordingto the equation:HNO, +LIOH → LINO, + H. Oa) 46b) 29c) 2d) 117) The mass of potassium hydroxide (KOH) to be dissolved in (100 ml) of water toobtain a solution of 0.25M concentration is:a) 1.4gb) 4.5gc) 0.025gd) 5.6g .8) Molarity (5g) of NaOH dissolved in 120 ml of solution the molar is :a) 0.75Mb) 1. 04Mc) 1.25Md) 0.5M9) How many grams of A1C1 should be dissolved, to prepare 1 liter of a solutionin which the concentration of Cl ions 0.6M?a) 240.3 gramsb) 80.1 gramsc) 26.7 gramsd) 41.1 grams10) For the following reaction:2A + 3B - 2ABAtomic a Weights A= 27 &B= 35.5The number of grams of AB. consisting of (12g) interaction of B:a) 26.2gMolecular weight AB = 133.5 g molb) 15.04gc) 20gd) 31.4ghp

Given actual yield of Cu = 6 x 10-5 mole Moles of CuSO4 = 8 x 10-5 mole Given equation is : CuSO4 +…

4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSO4 with a offer amount of Zn equal to 6 x 10 mol, the percentage yield of (Cu) according to the equation: CuSO(ag)+Zn(s) ZnSO. (aq) +Cu (s) a) 75% b) 83% c) 65% d) 90%.

4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSO4 with a offer amount of Zn equal to 6 x 10 mol, the percentage yield of (Cu) according to the equation: CuSO(ag)+Zn(s) ZnSO. (aq) +Cu (s) a) 75% b) 83% c) 65% d) 90%.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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