4) f(x)= cos x COS X %3D (5) f(x)=xsinx -1+ Cos nx

Q: If f(x) = 6 sin x + 9 cos a, then f'(x) =

A:

Q: ƒ' (4) = If f(x) = 3√√√x(x³ − 2√x + 2), find f'(4).

A: Given that

Q: f"(x) = 4x – 2 and f'(-3) = -3 and f(-3) = –6. Find f' (x) = %3D and find f(4) :

A: f''(x)=4x-2 f'(-3)=-3 , f(-3)=-6

Q: Find f(x), where f'(x) = sin(x)+ cos(x) + 1 and f(r) = 2. %3D %3D

A:

Q: Let f(x) = 2 csc (7x) f'(x) = - -14 cot (7x) csc (7x) X

A:

Q: If f'(x)=7x x-4 and f(4)= - 5, then what is f(5)?

A:

Q: f(x)=(6+x^3)^cos x Explain with steps

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Q: Find f'(x)) D f(x) (2) f(x) 3x³ +5x²12-2 2 6x -3x + 2x12 2

A:

Q: / If f(x) = 2x (Sinx+cosx) find. f'(x) = ' (5) =

A: Given function  f( x ) = 2x( sinx + cosx )

Q: can i get help step by step

A: We have to essentially find the integral of the given function

Q: f(x) then: f'(x) = f'(1) -

A: We are asked to find the derivatives of the function.

Q: If f(x) = - f'(x) = f'(5) = 2 sin r 3 + cos x 3 then

A:

Q: f(x)= 7tan-1(5sin(4x)) f'(x)=?

A: We have to find the derivative of the given function f(x)= 7tan-1(5sin(4x)).

Q: Show that the function f(x)=x^-4 +cos(-2x) is even, odd, or neither."

A: Given, f(x)= x^-4 +cos(-2x) f(x)= (1/x)4 + cos(-2x)

Q: f"(x) = 2x – 4 and f'(-1) = -1 and f(-1) = -3. Find f'(x) = and find f(4) = %3D

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Q: Find f such that f'(x) = 5x² + 7x − 9 and f(0) = 9. f(x) =

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Q: f(x) = sec x As x = π-/2, f(x) =  As x = π+/2, f(x) =

A:

Q: f' (x) = r(농) =

A:

Q: find where f'(c)=0 f(x)=-cos4x

A: Given, function

Q: If f(x) = f'(x) = f'(1) = 6x + 2 7x + 2 find: 2 (7x + 2)² 28 (7x+2)³ X

A:

Q: if f(x)=cosx-3tanx, then f′(x)= f'(5)=

A: The given function is f(x)=cosx-3tanx

Q: f'(x) = f(x) = cos(2x + 3)

A: Given query is to find the derivative.

Q: Let f(x) = 2 cos5 x f'(x) =

A: Given query is find the derivative.

Q: (x)= -5cos(cos(x5)) f'(x)=

A: Follow next step