4 Fe (s) + 3 02(g) → 2FE203 (s) S° 02 = 205 J/ mol. K, S° Fe = 27.3 J/ mol. K, S° Fe203 = 87.4 J/ molK %3D %3D Calculate AS°

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section18.2: Dispersal Of Energy: Entropy
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4 Fe (s) + 3 O2(g)
– 2FE2O3 (s)
S° 02 = 205 |/ mol. K, S° Fe = 27.3 J/ mol. K , S° Fe203 = 87.4
J/ molK
%3D
Calculate AS°
Transcribed Image Text:4 Fe (s) + 3 O2(g) – 2FE2O3 (s) S° 02 = 205 |/ mol. K, S° Fe = 27.3 J/ mol. K , S° Fe203 = 87.4 J/ molK %3D Calculate AS°
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