4 double KiloToPounds (double kilos) {5 // This statement intentionally has an error.6return (kilos / 2.204);}89 int main() {101112131415161718197double kilos;double pounds;cin >> kilos;pounds= KiloToPounds (kilos);cout << pounds << " lbs" << endl;return 0; 6.21 Lab training: Unit tests to evaluate your programAuto-graded programming assignments may use a Unit test to test small parts of a program. Unlike a Compare output test, which evaluatesyour program's output for specific input values, a Unit test evaluates individual functions to determine if each function:• is named correctly and has the correct parameters and return type• calculates and returns the correct value (or prints the correct output)This example lab uses multiple unit tests to test the Kilo ToPounds() function.Complete a program that takes a weight in kilograms as input, converts the weight to pounds, and then outputs the weight in pounds. 1kilogram = 2.204 pounds (lbs).Ex: If the input is:10the output is:22.04 lbsNote: Your program must define the functiondouble KiloToPounds (double kilos)The program below has an error in the KiloToPounds() function.1. Try submitting the program for grading (click "Submit mode", then "Submit for grading"). Notice that the first two test cases fail, butthe third test case passes. The first test case fails because the program outputs the result from the KiloToPounds() function, whichhas an error. The second test case uses a Unit test to test the Kilo ToPounds() function, which fails.2. Change the Kilo ToPounds() function to multiply the variable kilos by 2.204, instead of dividing. The return statement should be:return (kilos * 2.204); Submit again. Now the test cases should all pass.Note: A common error is to mistype a function name with the incorrect capitalization. Function names are case sensitive, so if a lab

Coded using C++.#include <iostream>using namespace std; double KiloToPounds(double kilos){ //change this statement such that kilos * 2.204 is returned instead of kilos/2.204 return (kilos * 2.204);} int main(){ double kilos; double pounds; cin >> kilos; pounds = KiloToPounds(kilos); cout << pounds << " lbs" << endl; return 0;}

Engineering

Computer Science

4 double Kilo ToPounds (double kilos) { 5 // This statement intentionally has an error. 6 return (kilos / 2.204); 7 } 8 9 int main() { 10 11 12 13 14 15 16 17 18 70 double kilos; double pounds; cin >> kilos; pounds KiloToPounds (kilos); cout << pounds << " lbs" << endl; return 0;

4 double Kilo ToPounds (double kilos) { 5 // This statement intentionally has an error. 6 return (kilos / 2.204); 7 } 8 9 int main() { 10 11 12 13 14 15 16 17 18 70 double kilos; double pounds; cin >> kilos; pounds KiloToPounds (kilos); cout << pounds << " lbs" << endl; return 0;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Below is the starting code for this homework assignment #include <stdio.h> //1. struct employees {     char name[20];     int ssn[9];     int yearBorn, salary; }; //2. struct employees e = {"kim deen", {1,2,3,4,5,6,7,8,9}, 1998, 35000}; //3. void display(struct employees *e) {     printf("%s", e->name);     printf(" %d%d%d-%d%d-%d%d%d%d", e->ssn[0],e->ssn[1],e->ssn[2],e->ssn[3],e->ssn[4],e->ssn[5],e->ssn[6],e->ssn[7],e->ssn[8]);     printf(" %d", e->yearBorn);     printf("\n$%d.", e->salary); } int main() {     display(&e);     return 0; }
#include <iostream> #include <string> using namespace std; int main() {    // Declare and initialize variables.    string employeeFirstName;    string employeeLastName;    double employeeSalary;    int employeeRating;    double employeeBonus;    const double BONUS_1 = .25;    const double BONUS_2 = .15;    const double BONUS_3 = .10;    const double NO_BONUS = 0.00;    const int RATING_1 = 1;    const int RATING_2 = 2;    const int RATING_3 = 3;    // This is the work done in the housekeeping() function            // Get user input        cout << "Enter employee's first name: ";    cin >> employeeFirstName;    cout << "Enter employee's last name: ";    cin >> employeeLastName;    cout << "Enter employee's yearly salary: ";    cin >> employeeSalary;    cout << "Enter employee's performance rating: ";    cin >> employeeRating;    // This is the work done in the detailLoop() function        // Use switch statement to…
C++ enum Major {COMPUTER_SCIENCE,             COMPUTER_SECURITY_INFO_ASSURANCE,             CYBER_SECURITY,             ELECTRICAL_ENGINEERING,             OTHER}; struct Name {     string first;     string last;     char    middleInitial; }; struct StudentRecord {     Name    studentName;     Major   major;     string email; }; StudentRecord student12; Suppose you are student12. Show the C++ statements used to fill in all of your information for your StudentRecord. Show how would you assign the third letter from the email field to a local char variable called myChar.
debug the code
token sequence
cion Completion Status: double max; int count; 10 11 12 cout>num; 13 14 15 16 max=num; 17 18 for (count=1; count>num; 21 max=larger (max, count); 22 23 24 cout=y) 34 return x,ys 35 36 return y,X3 37
//Below is the starting code for this homework assignment// #include <stdio.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; struct employees e = {"kim deen", {1,2,3,4,5,6,7,8,9}, 1998, 35000}; void display(struct employees *e) { printf("%s", e->name); printf(" %d%d%d-%d%d-%d%d%d%d", e->ssn[0],e->ssn[1],e->ssn[2],e->ssn[3],e->ssn[4],e->ssn[5],e->ssn[6],e->ssn[7],e->ssn[8]); printf(" %d", e->yearBorn); printf("\n$%d.", e->salary); } int main() { display(&e); return 0; }
//Below is the starting code for this homework assignment// #include <stdio.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; struct employees e = {"kim deen", {1,2,3,4,5,6,7,8,9}, 1998, 35000}; void display(struct employees *e) { printf("%s", e->name); printf(" %d%d%d-%d%d-%d%d%d%d", e->ssn[0],e->ssn[1],e->ssn[2],e->ssn[3],e->ssn[4],e->ssn[5],e->ssn[6],e->ssn[7],e->ssn[8]); printf(" %d", e->yearBorn); printf("\n$%d.", e->salary); } int main() { display(&e); return 0; }