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4) Answer the question in C++ A) What is wrong with the following code segment? enum CarType {GM, FORD, BMW}; int main() { CartType = BMW; return 0; } B) Assume that the addresses of x and y is 0x61feb8 and 0x61feb0, respectively. What will be the values of x, y, p, and q, respectively, when the following code runs successfully? int main() { int x; double y; int* p = &x; double* q = &y; *p = 3; *q = 3.14; increaseByOne(p, q); cout << x << " " << y << endl; cout << p << " " << q << endl; return 0; } void increaseByOne(int*& p1, double* q1) { (*p1)++; (*q1)++; p1++; q1++; } The four value:

4) Answer the question in C++ A) What is wrong with the following code segment? enum CarType {GM, FORD, BMW}; int main() { CartType = BMW; return 0; } B) Assume that the addresses of x and y is 0x61feb8 and 0x61feb0, respectively. What will be the values of x, y, p, and q, respectively, when the following code runs successfully? int main() { int x; double y; int* p = &x; double* q = &y; *p = 3; *q = 3.14; increaseByOne(p, q); cout << x << " " << y << endl; cout << p << " " << q << endl; return 0; } void increaseByOne(int*& p1, double* q1) { (*p1)++; (*q1)++; p1++; q1++; } The four value:

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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4) Answer the question in C++

A) What is wrong with the following code segment?

enum CarType {GM, FORD, BMW};

int main()

{

       CartType = BMW;

       return 0;

}

 

B) Assume that the addresses of x and y is 0x61feb8 and 0x61feb0, respectively. What will be the values of x, y, p, and q, respectively, when the following code runs successfully?

int main() {
  int x;
  double y;

  int* p = &x;
  double* q = &y;

  *p = 3;
  *q = 3.14;

  increaseByOne(p, q);
  cout << x << " " << y << endl;
  cout << p << " " << q << endl;
  return 0;

}
void increaseByOne(int*& p1, double* q1)
{
    (*p1)++;
    (*q1)++;
    p1++;
    q1++;
}

The four value:

 
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