The text in the image poses a probability question related to expected value (EV):"A game has a 10 dollar buy-in. You have 20% to win nothing, 20% to win 5 dollars, 30% to break even, and 30% to win 20 dollars. What is the game's EV?"To calculate the expected value, we need to consider the probability and outcome of each event:- 20% chance to win nothing: \$0- 20% chance to win 5 dollars: \$5- 30% chance to break even: \$10- 30% chance to win 20 dollars: \$20Calculate the expected value (EV) using the formula:EV = (Probability of Outcome 1) * (Outcome 1) + (Probability of Outcome 2) * (Outcome 2) + ...Here is the breakdown:EV = (0.20 * \$0) + (0.20 * \$5) + (0.30 * \$10) + (0.30 * \$20)Explain each calculation:1. The chance of winning nothing results in zero return.2. The chance of winning $5 contributes to part of the expected winnings.3. The chance of breaking even simply returns the initial buy-in.4. The chance of winning $20 significantly affects the expected value.Substitute the calculations and solve for the EV to determine the financial expectation of playing the game.This represents a basic approach to understanding probability and how expected value is used in decision making in potential gamble-like scenarios.

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Description: The text in the image poses a probability question related to expected value (EV):"A game has a 10 dollar buy-in. You have 20% to win nothing, 20% to win 5 dollars, 30% to break even, and 30% to win 20 dollars. What is the game's EV?"To calculate th

Break even means that amount received is equal to the cost which is equal to 10. The distribution…

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4 A game has a 10 dollar buy in. You have 20% to win nothing, 20% to win 5 dollars, 30% to break even, and 30% to win 20 dollars. What is the games

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