4 -5 -9] 0 -3 1 -2 -3 The matrix A has an eigenvalue A = -3. 1
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.1: Eigenvalues And Eigenvectors
Problem 66E: Show that A=[0110] has no real eigenvalues.
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Need help with first part for matrix A
![4 -5 -9
The matrix A = 0
0 -3 has an eigenvalue A = -3.
1
-2 -3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0e989a36-a976-4f9a-8f93-2801096d9bdd%2F09e60bbf-59a8-4f11-9a85-7db958402e48%2Fm550x2o_processed.png&w=3840&q=75)
Transcribed Image Text:4 -5 -9
The matrix A = 0
0 -3 has an eigenvalue A = -3.
1
-2 -3
![Find an eigenvector for this eigenvalue.
Note: You should solve the following problem WITHOUT computing all eigenvalues.
5 2
-3 3 has an eigenvector i
3 1
6
The matrix B
-5
2
3
Find the eigenvalue for this eigenvector.
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0e989a36-a976-4f9a-8f93-2801096d9bdd%2F09e60bbf-59a8-4f11-9a85-7db958402e48%2Fyv524zv_processed.png&w=3840&q=75)
Transcribed Image Text:Find an eigenvector for this eigenvalue.
Note: You should solve the following problem WITHOUT computing all eigenvalues.
5 2
-3 3 has an eigenvector i
3 1
6
The matrix B
-5
2
3
Find the eigenvalue for this eigenvector.
=
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