-4-4-2-4-4|-2-4-4 Calculate the probability distribution function of x, i.e. the function pr(x). First, fill in the first row with the values of x. Then fill in the appropriate probabilities in the second row. Value x of X O|O

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O RANDOM VARIABLES AND DISTRIBUTIONS
Shasia v
Discrete probability distribution: Word problems
-4|-4|-2|-4
-4|-2|-4-4
Aa
Calculate the probability distribution function of x, i.e. the function
- (x).
Px
First, fill in the first row with the values of x. Then fill in the appropriate
probabilities in the second row.
Value x of X
Explanation
Check
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Transcribed Image Text:O RANDOM VARIABLES AND DISTRIBUTIONS Shasia v Discrete probability distribution: Word problems -4|-4|-2|-4 -4|-2|-4-4 Aa Calculate the probability distribution function of x, i.e. the function - (x). Px First, fill in the first row with the values of x. Then fill in the appropriate probabilities in the second row. Value x of X Explanation Check 20/IMCGIOW HILEGucotion. All Rights Resenved. Terms of Use I Privacy Accessibility II
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O RANDOM VARIABLES AND DISTRIBUTIONS
Shasia v
Discrete probability distribution: Word problems
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of
"heads" (h) and "tails" (1) which we write hth, ttt, etc. For each outcome, let
R be the random variable counting the number of tails in each outcome.
For example, if the outcome is hht, then R (hht)= 1. Suppose that the random
variable x is defined in terms of R as follows: x=R² – 3R– 2. The values of x
are thus:
Outcome h ht thh ttt |htt tth hhh ththth
Value of
-4-4|-2|- 4|-4|-2|-4-4
Explanation
Check
2UZIMCUraw HilLEGcation. AlL Rights Reserved.
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Transcribed Image Text:I Home | iCampus Bb Week 9 - MAT300457VA016-121... A ALEKS - Shasia Gibbs - Learn O RANDOM VARIABLES AND DISTRIBUTIONS Shasia v Discrete probability distribution: Word problems An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (1) which we write hth, ttt, etc. For each outcome, let R be the random variable counting the number of tails in each outcome. For example, if the outcome is hht, then R (hht)= 1. Suppose that the random variable x is defined in terms of R as follows: x=R² – 3R– 2. The values of x are thus: Outcome h ht thh ttt |htt tth hhh ththth Value of -4-4|-2|- 4|-4|-2|-4-4 Explanation Check 2UZIMCUraw HilLEGcation. AlL Rights Reserved. Terms of Use I Privacy Accessibility
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