Identify the means and the extremes. 4.12Means:and1.15Extremes:and2.6:9 -4:6Means:andExtremes:and

1) 45=1215 Means = 5 and 12 Extremes = 4 and 15

Answered: 4 12 5 15 Means: and 1. Extremes: and…

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

ChapterP: Preliminary Concepts

SectionP.CT: Test

Problem 1CT

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4 12 5 15 Means: and 1. Extremes: and 2. 6:9 - 4:6 Means: and Extremes: and