4) . Determine the friction drag on its hull and the power required to overcome this force if the velocity of the ship is 2 m/s. Consider both laminar and turbulent boundary layers. Take p = 1030 kg/m³ and u = 1.14x10 N-s/m². Hint: Fpf = CofA(pU²/2) and Cpf = Chapter 11: The oil tanker has a smooth surface area of 5.0x10 m² in contact with the sea. 0.455 1700 (log10Reį)2.58 ReL 2 m/s 300 m
4) . Determine the friction drag on its hull and the power required to overcome this force if the velocity of the ship is 2 m/s. Consider both laminar and turbulent boundary layers. Take p = 1030 kg/m³ and u = 1.14x10 N-s/m². Hint: Fpf = CofA(pU²/2) and Cpf = Chapter 11: The oil tanker has a smooth surface area of 5.0x10 m² in contact with the sea. 0.455 1700 (log10Reį)2.58 ReL 2 m/s 300 m
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Fluid

Transcribed Image Text:4) :
Chapter 11: The oil tanker has a smooth surface area of 5.0x10 m2 in contact with the sea.
Determine the friction drag on its hull and the power required to overcome this force if the velocity of the
ship is 2 m/s. Consider both laminar and turbulent boundary layers. Take p = 1030 kg/m and u =
1.14x103 N-s/m².
0.455
1700
Hint: Fpf = CpfA(pU? /2) and Cpf
%3D
(log10 ReL)2.58
ReL
2 m/s
300m
7
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