k*3m3mAс3m4m(10)(5)20 KN3m(10)D(10)BAnswers in structures lectures :Analyze the structure as shown in Fig. belowsArea = ( ) cm² Ib=100 * 10³ cm4, E = 20*10³ kN/cm²4m(5)(10)1E2Members CD, BD, DE, EF, DF & CF are trussmembers'Member AB is a frame member·30.6kNimA15.1 KN20 KNETABS Answers: R₁ = 15.103 kN; MA= 30.61 kN.m, FBD = 4.897 KN4.9 KN

Answered: * 3m 3m A 3m 4m (10) (5) 20 KN 3m F…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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k
*
3m
3m
A
с
3m
4m
(10)
(5)
20 KN
3m
(10)
D
(10)
B
Answers in structures lectures :
Analyze the structure as shown in Fig. belows
Area = ( ) cm² Ib=100 * 10³ cm4, E = 20*10³ kN/cm²
4m
(5)
(10)
1
E
2
Members CD, BD, DE, EF, DF & CF are truss
members'
Member AB is a frame member
·30.6kNim
A
15.1 KN
20 KN
ETABS Answers: R₁ = 15.103 kN; MA= 30.61 kN.m, FBD = 4.897 KN
4.9 KN

Expert Solution

Step 1 Introduction

The given truss is statically determinate truss and can be analyzed using the equations of equilibrium. The method used to analyze the member forces are method of joints and method of sections. The given truss is symmetrical, and the area of each member is given in the figure.

$E = 20 \times 10^{3} \frac{k N}{c m^{2}}$

$I = 10^{5} c m^{4}$

The given frame can be analyzed using the unit load method. The deflection of truss at point B will be equal to the deflection of beam AB at point B.

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