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3c. 4b. Find AC. AC = CE: 10.5 IC: 4.5 B F 4 A E2 7 C 5 H 1.5 5 D Exceeds: Given a more complicated diagram, I can solve for missing lengths, using secant and tanger

3c. 4b. Find AC. AC = CE: 10.5 IC: 4.5 B F 4 A E2 7 C 5 H 1.5 5 D Exceeds: Given a more complicated diagram, I can solve for missing lengths, using secant and tanger

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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O 3c. 4b. Find AC. AC = CE: 10.5 IC: 4.5 4. Explain why, mDE = 2mBC, given AB = EB. B D F 4 1 E 2 5 7 G C H 1.5 5 Exceeds: Given a more complicated diagram, I can solve for missing lengths, using secant and tangents of circles. D
Transcribed Image Text:O 3c. 4b. Find AC. AC = CE: 10.5 IC: 4.5 4. Explain why, mDE = 2mBC, given AB = EB. B D F 4 1 E 2 5 7 G C H 1.5 5 Exceeds: Given a more complicated diagram, I can solve for missing lengths, using secant and tangents of circles. D
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